Ask question

Ask question

All categories

4 years ago

13

A school custodian discovered a leak in a water pipe. The custodian found that 1920 fluid ounces of water leaked out. How many g

allons of water is this? Use the conversation factor 1 gallon over 128 fluid ounces

2 answers:

shtirl [24]4 years ago

8 0

1920 fL/128G
= 15 Gallons

oee [108]4 years ago

4 0

It would be 15 Gallons

You might be interested in

Due tomorrow deeply appreciated if done

fiasKO [112]

This is unreadable try submitting a more clear picture. i can bairly read the first problem i think it says 8(3x+4)=2(17x????)

6 0

3 years ago

Whats 3x3+4 use pemdas ?

Romashka [77]

Answer:

13

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

PLZ HELP AND IF U TAKE MY POINTS I WILL REPORT U AN WHO EVER HELPS I WIL GIVE BRAINIEST

Sphinxa [80]

Answer:

the second one I can't give a explanation cause my wrist is broken so it's harder to type hope this helps

6 0

3 years ago

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

7 0

3 years ago

Anybody knows the answer??

monitta

Answer:

m=2 and b=4

Step-by-step explanation:

hope this helps

8 0

3 years ago

Read 2 more answers