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seropon [69]
3 years ago
9

What is 76+1 in math

Mathematics
2 answers:
vodomira [7]3 years ago
6 0

Answer:

77

Step-by-step explanation:

IgorC [24]3 years ago
4 0

Answer:

Step-by-step explanation:

The answer is ✨77✨

There is your

answer

Plain and simple

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My soccer team has 16 players. I have to choose a starting lineup of a goalie and 10 regular players (the regular players are in
ASHA 777 [7]

Answer:

3003

Step-by-step explanation:

We want to find out how many ways we can choose 10 players among 15 players (since the goalie is not interchangeable)

The number of different lineups you can have can be found by using combination:

^{15}C_{10} = \frac{15!}{(15 - 10)! 10!}\\ \\= \frac{15!}{5! * 10!} \\\\= 3003

There are 3003 different lineups that can be chosen.

6 0
3 years ago
How many triangles can be made with a 70 degree angle a 30 degree angle and an 80 degree angle​
uranmaximum [27]

Answer:

There are infinite number of triangles that could be achieved with those angles.

To picture this, we only have to imagine a triangle that is either smaller or bigger than the one at hand.

Tracing a series of paralell lines (which guarantee that the angles are being kept),  we can draw triangles for infinite values of x,y and z.

5 0
3 years ago
Hi can you please solve these problems for me? I'll give you all 5 stars :T
Sunny_sXe [5.5K]

Answer:

number 1. answer 3x+6

number 2. answer 2r-8

number 3. answer 4y+8

number 4. answer 24-6x

3 0
3 years ago
Six men are aboard the International Space Station.
kolezko [41]
There are officially two people aboard the space station
Answer: 2
8 0
3 years ago
In the isosceles △ABC m∠ACB=120° and AD is an altitude to leg BC . What is the distance from D to base AB , if CD=4cm?
7nadin3 [17]

Correct answer is: distance from D to AB is 6cm

Solution:-

Let us assume E is the altitude drawn from D to AB.

Given that m∠ACB=120° and ABC is isosceles which means

m∠ABC=m∠BAC = \frac{180-120}{2}=30

And AC= BC

Let AC=BC=x

Then from ΔACD , cos(∠ACD) = \frac{DC}{AC} =\frac{4}{x}

Since DCB is a straight line m∠ACD+m∠ACB =180

                                              m∠ACD = 180-m∠ACB = 60

Hence cos(60)=\frac{4}{x}

          x=\frac{4}{cos60}= 8

Now let us consider ΔBDE, sin(∠DBE) = \frac{DE}{DB} =\frac{DE}{DA+AB} = \frac{DE}{4+8}

DE = 12sin(30) = 6cm

7 0
3 years ago
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