Answer:
your answer is 20%
Step-by-step explanation:
16/80 = .2 = 20%
Answer:
g(1) = 6
Step-by-step explanation:
Substituting 1 into g(x):
g(1) = 1(1) + 5
= 1 + 5
= 6
<em>Hope this helps and be sure to have a wonderful time ahead at Brainly! :D</em>
Answer:
The amount of change she received is
$16.1
Step-by-step explanation:
1.what is asked in the problem?
We are to find how much change she received
what are the given facts?
She bought:
notebook which cost 23.75; a set of colored pens which cost 36.20 and a liquid eraser which cost 23.95
She gave the cashier $100
2.what operation to be used to solve the problem ?
Addition and Subtraction operation
3.solve
= $100 - ($23.75 + $36.20 + $23.95)
= $100 - $83.9
= $16.1
The amount of change she received is
$16.1
Answer:
The following measurements are:
(Option #4)
(Option #7)
(Option #5)
(Option #2)
Step-by-step explanation:
To begin, we can find the measure of 
by applying the inscribed angle theorem: an angle θ inscribed in a circle is half of the central angle 2θ that subtends the same arc on the circle.
Since the intercepted arc (RS) is 46 degrees, we have:
Next, we can find the measure of arc QT using the same theorem. So,
Notice that the chord RT is actually a diameter. From the theorem about the inscribed angle including a diameter, we know that the intercepted arc will have a measure of 
. Since the arc ST is part of the arc RST, and we know RS is 
, we can set up and solve this equation:
We can use the same idea to find RQ. We know that RQT is and QT is 
, so:
<h3>
Answer: 128.74 square meters</h3>
=========================================================
Explanation:
The area of the garden only (ignore the circular pathway) is approximately
A = pi*r^2
A = 3.14*20^2
A = 1256
The area of the garden plus the path is approximately
A = pi*r^2
A = 3.14*21^2
A = 1384.74
Notie how I added on 1 meter to increase the radius to 21
Subtract the two circle areas to get the area of the circular ring.
1384.74 - 1256 = 128.74
The units for all of the areas mentioned are "square meters".
