Question

2(i + 3) > 4(1 - i)​

Answer 1

$2(i+3)>4(1-i)$

Distribute 2 in (i+3) and 4 in (1-i)

$2i+6>4-4i$

Move -4i to another side and 6 to another side. When moving to another side, you'll have to change the sign/operator to opposite (Plus -> Minus, Multiply -> Divide)

$2i+4i>4-6\\6i>-2$

For this part, move 6 to divide -2.

$i>\frac{-2}{6} \\i>\frac{-1}{3}\\i>-\frac{1}{3}$

Whenever either a numerator or a denominator is in negative, we can pull out the negative in the middle of fraction.

Note that i is the symbol of imaginary number - as defined -  i = √-1 But for this one, It's just a variable if I assume.

Thus, the answer is i > -1/3