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Dima020 [189]
3 years ago
10

Precipitation for the month of March was 6 ½ inches less than average. In April, the precipitation was 2 ⅜ inches less than aver

age. How many inches below average was the precipitation for both March and April?
Mathematics
1 answer:
deff fn [24]3 years ago
7 0

Answer:

The precipitation for both March and April was 8 7/8 inches below average

Step-by step explanation;

For the month of march, precipitation was 6 1/2 inches less than average

For the month of April, precipitation was 2 3/8 inches left.

Now we want to calculate how many inches less than average was precipitation in both wants

What we simply do here is to add the inches with which they were both left than average in both months

That would be;

6 1/2 + 2 3/8

= 13/2 + 19/8 = (52 + 19)/8 = 71/8 = 8 7/8 inches

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Answer:

No is something worng

Step-by-step explanation:

y= 9/8 * x - 1

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Anyone know questions 9 and 10
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Answer:

8.j     9.b   10.f    11.a

Step-by-step explanation:

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Which is true about the degree of the sum and difference of the polynomials 3x5y – 2x3y4 – 7xy3 and –8x5y + 2x3y4 + xy3?
Alekssandra [29.7K]
<span>First we have to find the sum and the difference of those polynomials- The sum is: ( 3 x^5y - 2 x^3y^4 - 7 xy^3 ) + ( - 8 x^5y + 2 x^3y^4 + xy^3 ) = 3 x^5 - 2 x^3y^4 - 7xy^3 - 8 x^5y + 2 x^3y^4 + xy^3 = - 5 x^5y - 6 xy^3. And the difference: ( 3 x^5y - 2 x^3y^4 - 7 xy^3 ) - ( - 8 x^5y + 2 x^3y^4 + xy^3 ) = 3 x^5y - 2 x^3y^4 - 7 xy^3 + 8 xy^5 - 2 x^3y^4 - xy^3 = 11 xy^5 - 4 x^3y^4 - 8xy^3. The highest exponent in both polynomials is 5. Answer: The degree of the polynomials is 5.</span>
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What is 38 in denary in base 8
Naily [24]
First divide by 8:_

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4 0
3 years ago
From a group of 3 men and 4 women, a delegation of 2 is selected. What is the expected number of men in the delegation?
Ostrovityanka [42]

Answer:

The expected number of men in the delegation is 0.86.

Step-by-step explanation:

Number of men = 3

Number of women = 4

A delegation of 2 is selected.

Let X be the number of men selected. So, the possible values of X are 0,1,2.

P(X=0)=\dfrac{^3C_0\times ^4C_2}{^7C_2}=\dfrac{2}{7}

P(X=1)=\dfrac{^3C_1\times ^4C_1}{^7C_2}=\dfrac{4}{7}

P(X=2)=\dfrac{^3C_2\times ^4C_0}{^7C_2}=\dfrac{1}{7}

The expected number of men in the delegation is

E(x)=0\times P(X=0)+1\times P(X=1)+2\times P(X=2)

E(x)=0\times \dfrac{2}{7}+1\times \dfrac{4}{7}+2\times \dfrac{1}{7}

E(x)=\dfrac{6}{7}

E(x)\approx 0.86

Therefore, the expected number of men in the delegation is 0.86.

4 0
3 years ago
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