The only factors of 73 are itself and one so it is a prime number.
Answer:
1.2
Step-by-step explanation:
Because the probability cannot be over 1 (assuming 1 is 100%) you can't have a 120% chance.
-8x-y=4
-
-8x-y=9
=
0≠9. As a result, this system has no solution. Hope it help!
Answer:
$172,806.37.
Step-by-step explanation:
Total = [ P(1+r/n)^(nt) ] + [ PMT × (((1 + r/n)^(nt) - 1) / (r/n)) ] * (1 + r/n)
is the formula for the amount left after the first 7 years where the money is deposited at the beginning of each month and P = initial amount, PMT = monthly payment, r = rate as a decimal and t = time in years.
Total after the first 7 years
= [ 200(1+0.09/12)^(7*12) ] + [ 200 × (((1 + 009/12)^(7*12) - 1) / (0/09/12) ] * (1 + 0.09/12)
= 374.64 + (200 * 0.8732019633) / (0.09/12) * (1 + 0.09/12)
= 374.64 + 23485.386 * 1.0075
= $24.036.17
Total after a further 22 years:-
= 24.036.17(1 + 0.09/12)^(12*22)
= $172,806.37 (answer).
Answer:
Both buses will arrive at the stop at 6:52 AM
Step-by-step explanation:
Wilkenson Bus = Arrives every 21 minutes
Harris Road Bus = Arrives every 15 minutes
Let's find the Least Common Multiple (LCM) of 21 and 15. LCM is found, listing the prime factors of each numbers and then multiplying each factor the greatest number of times it occurs in either numbers:
LCM 21 = 3 × 7
LCM 15 = 3 × 5
LCM (21 , 15) = 3 × 7 × 5 = 105
In 105 minutes both buses will arrive at the same time again
105 minutes = 1 h 45 min
5:07 AM + 1h 45 min = 6:52 AM
