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Tcecarenko [31]
3 years ago
12

Triangle TRI has a base of m centimeters and a height of n centimeters. Rectangle REC and a width of m centimeters. Use complete

sentences to compare the areas of triangle...please answer correctly, NOT JUST FOR FREE POINTS​
Mathematics
1 answer:
vichka [17]3 years ago
3 0

Answer:Given a rectangle, the general equation for the perimeter is P=2l+2w and area is A=lw where l is the length and w is the width.

Let x = width and x+10 = length

So the equation to solve becomes 40=2x+2(x+10) so x=5 thus the width is 5m and the length is 15m.

Thus the area is 5⋅15=75m2

Step-by-step explanation:

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RideAnS [48]
(-1,-4) this is saying that when x=-1, y=-4. Plugging it into the line equation y=4x gives
(- 4) = 4( - 1)
Which is correct.
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Let f(x) = x ^ 2 - x - 2 and g(x) = - 6x - 8. Find g(2) and f(g(2)). Mathfrak g (2)= Box (Simplify your answer. ) f(g(2)) = ( Si
jek_recluse [69]

The value of the function f(g) after simplifying and putting 2 in place of <em>x</em> is -20 and the value of f(g(2)) is 418.

<h3>What is composite function?</h3>

When a function is written inside the another function, then such function is called the composite function.

The first function given in the problem is,

f(x) = x^2 - x - 2

The second function given,

g(x) = - 6x - 8

To find out the value of g(2), put the 2 on place of variable x in the above equation as,

g(2) = - 6(2) - 8\\g(2)=-12-8\\g(2)=-20

The composite function f(g(x)) can be given as,

f(g(2))= (-20)^2 - (-20) - 2\\f(g(2))=418

Thus, the value of the function f(g) after simplifying and putting 2 in place of <em>x</em> is -20 and the value of f(g(2)) is 418.

Learn more about the composite function here:

brainly.com/question/10687170

5 0
2 years ago
A man weekly pay is $x. he spends 1/2 of his pay on food and 1/3 on rent
vekshin1

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7 0
3 years ago
Mary is the last person to get on a ferris wheel ride at a fair (the ride begins once she is on). The ferris wheel has a radius
Aleks [24]

Answer:

a) For sketch see attached picture.

 y=-8cos(\pi t)+10

b) Mary will be able to enjoy the scenery for a total of 1.68 min or about 101 seconds.

Step-by-step explanation:

a) In order to find the algebraic representation of the problem, we must start by drawing a sketch of what the problem looks like (see attached picture). Next, we can analyze it to see what function better fits the situation. In this case, since the ride starts at the lowest point, then we are talking about a negative cos function. A cos function has the followng general form:

y= Acos(\omega t - \phi) + C

where:

A= amplitude

\omega=angular speed

t=time

\phi= phase shift

C= vertical shift.

In this case the amplitude will be the radius of the ferris wheel, so:

A=-8

it's negative because it starts at the lowest point.

the angular speed is the angle the ride will move in a given amount of time. In this case:

\omega=\frac{\pi rad}{1 min}

\omega=\pi rad/min

There will be no phase shift for this problem.

the vertical shift is the height of the platform, so:

C= 2

so the algebraic expression is:

y=-8cos(\pi t)+10

b) In order to find the total time for which she will enjoy the ride we must start by building an inequality:

-8cos(\pi t)+10>12

and solve it for t. We can start by turning it into an equation, solve it for t and find the answers that can be found into its domain, in this case D=[0,4]

so we get:

-8cos(\pi t)+10=12

we subtract a 10 from both sides so we get:

-8cos(\pi t)=2

and divide 8 to both sides so we get:

cos(\pi t)=-\frac{1}{4}

Next, we take the inverse cosine to both sides and get different answers:

\pi t = 1.823+2\pi n

and

\pi t=4.46 + 2\pi n

we take both equations and divide them into pi so we get:

t = 0.58+2 n

and

t=1.42 + 2n

so now we find the possible answers that are between 0 and 4 minutes, this is for n=0 and 1, so we get the following times:

t={0.58, 1.42, 2.58, 3.42} min

we can now build our possible intervals for which the ferris wheel is higher than 12 m so we get the following intervals:

(0, 0.58) (0.58, 1.42) (1.42, 2.58) (2.58, 3.42) and (2.58, 4)

so we pick a test value for each of the intervals and test it on our equation. If the equation gives us a number that is greater than 12, then we have a valid interval. If we get a value that is less than 12, then we just discard that interval.

for (0, 0.58) we use 0.5 and get an answer of 10. We discard this interval.

for (0.58, 1.42) we use 1 and get an answer of 18. This is a valid interval.

for (1.42, 2.58) we use a 2 and get an answer of 2. We discard this interval.

for (2.58, 3.42) we use a 3 and get an answer of 18. This is a valid interval.

and finally, for (2.58, 4) we use a 3.5 and get an answer of 10. We discard this interval

So we have two valid intervals now: (0.58, 1.42) and (1.42, 2.58). So now we can use them to find the time for which Mary will enjoy the scenery.

t_{1}=1.42min-0.58min=0.85min

t_{2}=2.58min-1.42min=0.85min

t_{total}=0.85min+0.85min

t_{total}=1.68min

so:

Mary will be able to enjoy the scenery for a total of 1.68 min or about 101 seconds.

8 0
3 years ago
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