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Tcecarenko [31]
2 years ago
12

Triangle TRI has a base of m centimeters and a height of n centimeters. Rectangle REC and a width of m centimeters. Use complete

sentences to compare the areas of triangle...please answer correctly, NOT JUST FOR FREE POINTS​
Mathematics
1 answer:
vichka [17]2 years ago
3 0

Answer:Given a rectangle, the general equation for the perimeter is P=2l+2w and area is A=lw where l is the length and w is the width.

Let x = width and x+10 = length

So the equation to solve becomes 40=2x+2(x+10) so x=5 thus the width is 5m and the length is 15m.

Thus the area is 5⋅15=75m2

Step-by-step explanation:

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Express 90 as a product of its prime number
VMariaS [17]
The prime factorization of 90 is 2*3^2*5

3 0
2 years ago
No is divisible by 7 if n is divided by 2 3 4 5 the remainder is 1 what is the smallest value that n could b
kvv77 [185]

Answer: 301

Step-by-step explanation:

Since, The LCM of numbers given numbers 2 ,3,  4 and 5 is 60.

Thus, the number that gives 1 as reminder and is the multiple of 7 is  60 n + 1

Where n is any positive integer,

Since, For n = 5,

The number is, 60\times 5 + 1 = 300 + 1 = 301

Which is divisible by 7.

Thus, the required number is 301.

Note : For n = 1, 2 3 and 4, numbers are 61, 121, 181 and 241

But they are not the multiple of 7.

7 0
3 years ago
Read 2 more answers
HALP MEEEEEEE!!!!!!!!!!!!!!!!!!!!!
Lesechka [4]

Answer: 4

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Determine an equation of a Quadratic function
Pepsi [2]

Answer:

y = -4x² + 32x - 48

Step-by-step explanation:

The standard form of a quadratic equation is  

y = ax² + bx + c

We must find the equation that passes through the points:

(2, 0), (6,0), and (3, 12)

We can substitute these values and get three equations in three unknowns.

0 = a(2²) + b(2) + c

0 = a(6²) + b(6) + c

12 = a(3²) + b(3) + c

We can simplify these to get the system of equations:

(1)   0 =    4a + 2b + c

(2)  0 = 36a + 6b + c

(3) 12 =   9a + 3b + c

Eliminate c from equations (1) and (2). Subtract (1) from (2).

(4) 0 = 32a + 4b

Eliminate c from equations (2) and (3). Subtract (3) from (2).

(5) -12 = 27a - 3b

Simplify equations (4) and (5).

(6)  0 = 8a + b

(7) -4 = 9a  - b

Eliminate b by adding equations (6) and (7).

(8) a = -4

Substitute (4) into (6).

    0 = -32 + b

(9) b =  32

Substitute a and b into (1)

0 = 4(-4) + 2(32) + c

0 = -16 + 64 + c

0 = 48 + c

c = -48

The coefficients are

a= -4, b = 32, c = -48

The quadratic equation is

y = -4x² + 32x - 48

The diagram below shows the graph of your quadratic equation and the three points through which it passes.

4 0
3 years ago
What is the results of adding these two equations?<br> 6x+2y=-2<br> 3x-2y=-5
Bess [88]

Answer:

x=-7/9, y=4/3. (-7/9, 4/3).

Step-by-step explanation:

6x+2y=-2

3x-2y=-5

-----------------

9x=-7

x=-7/9

6(-7/9)+2y=-2

-42/9+2y=-2

2y=-2-(-42/9)

2y=-2+42/9

2y=-18/9+42/9

2y=24/9

y=(24/9)/2

y=(24/9)(1/2)

y=24/18

y=4/3

5 0
3 years ago
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