Quadratic is in the form
ax^2+bx+c=0
so distribute and stuff and simplify
remember
a(b+c)=ab+ac
(x+2)^2+5(x+2)-6=0
remember order of opertaions
(x+2)(x+2)+5(x+2)-6=0
x^2+4x+4+5x+10-6=0
add like terms
x^2+9x+8=0
Answer:
(x - 3)² + (y + 9)² = 25
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k ) are the coordinates of the centre and r is the radius
Given area = 25π , that is
πr² = 25π ( divide both sides by π )
r² = 25 ( take the square root of both sides )
r =
= 5
With centre (h, k) = (3, - 9 ) and r = 5 , then
(x - 3)² + (y - (- 9) )² = 5² , that is
(x - 3)² + (y + 9)² = 25
We have the following function:
f (x) = 2a ^ 2b + 3a ^ 3b ^ 2 + 2a ^ 2b ^ 4
We note that the function depends on x because it is f (x).
However, there is no variable x in the function.
Therefore we can assume that the function is constant, since:
a = constant
b = constant
Therefore, the degree of the function is zero
Answer:
The function is zero degree.
I'm pretty sure it should be the 45. or A
Answer: The student could use large intervals (what he counts by)
Step-by-step explanation: