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Phantasy [73]
3 years ago
5

HELP PLZ I AWARD BRAINLIEST TO FIRST PERSON! PLZZZZZZ HELP MATH

Mathematics
1 answer:
dimaraw [331]3 years ago
5 0

Answer:

i dont sorry but i could go away bye see you soon hahhah your idiot your super duper brianless

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John drove from house to work at an average speed of 30 mph, trip took 40 minutes. How far in meters is his house to work?
AysviL [449]

Answer:

20 meters

Step-by-step explanation:

Firstly we need to know that distance = speed * time

In this particular question, we have the time and the speed, we are only told to find the distance.

Now as we can see, the units are not consistent. While the average speed is 30mph, the time is not in hours but minutes. So practically, we have to convert the time to hours.

Since there are 60 minutes in an hour, the number of hours in 40 minutes would be 40/60 = 2/3 hours.

Now we can proceed to find the distance. We simply multiply the average speed with the time.

Hence, that is 30 * 2/3 = 20 meters

5 0
3 years ago
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
3 years ago
Solve the following system of equations algebraically:<br> 4x - 5y = 18<br> 3x – 2y = 10
fiasKO [112]

Answer:

D

Step-by-step explanation:

Given the 2 equations

4x - 5y = 18 → (1)

3x - 2y = 10 → (2)

Multiplying (1) by 3 and (2) by - 4, then adding will eliminate the x- term

12x - 15y = 54 → (3)

- 12x + 8y = - 40 → (4)

Add (3) and (4) term by term to eliminate x, that is

- 7y = 14 ( divide both sides by - 7 )

y = - 2

Substitute y = - 2 into either of the 2 equations and solve for x

Substituting into (1)

4x - 5(- 2) = 18

4x + 10 = 18 ( subtract 10 from both sides )

4x = 8 ( divide both sides by 4 )

x = 2

solution is (2, - 2 ) → D

8 0
3 years ago
If you want to create a perfect curve, which tool would be most helpful?
luda_lava [24]
The most usfull tool would be a compas
4 0
3 years ago
Read 2 more answers
Please help me on this <br><br> Simplify (12^2)^4
nika2105 [10]

(12^2)^4

= 12^(2*4)

= 12^8 (or 429,981,696)

7 0
3 years ago
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