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2 years ago

Write an equation that expresses the following relationship.

Mathematics

1 answer:

Naya [18.7K]2 years ago

5 0

U varies inversely which means p³ will come as a denominator of the constant k.

Therefore, The equation formed will be:

$\sf \: u = \frac{k}{ {p}^{3} }$

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A circle has a circumference of 7,850 units. What is the radius of the circle?

ioda

Answer:1250 units

Step-by-step explanation:

circumference=7850

Radius=?

Radius=circumference ➗ (2xπ)

Radius=7850 ➗ (2 x 3.14)

Radius=7850 ➗ (6.28)

Radius=1250 units

8 0

3 years ago

A line can be defined in general form by the equation

Sveta_85 [38]

I am pritty shure i dont know

6 0

4 years ago

Clark and Lana take a 30-year home mortgage of $128,000 at 7.8%, compounded monthly. They make their regular monthly payments fo

svp [43]

Answer:

Step-by-step explanation:

From the given information:

The present value of the house = 128000

interest rate compounded monthly r = 7.8% = 0.078

number of months in a year n= 12

duration of time t = 30 years

To find their regular monthly payment, we have:

$PV = P \begin {bmatrix} \dfrac{1 - (1 + \dfrac{r}{n})^{-nt}}{\dfrac{r}{n}} \end {bmatrix}$

$128000 = P \begin {bmatrix} \dfrac{1 - (1 + \dfrac{0.078}{12})^{- 12*30}}{\dfrac{0.078}{12}} \end {bmatrix}$

128000 = 138.914 P

P = 128000/138.914

P = $921.433

∴ Their regular monthly payment P = $921.433

To find the unpaid balance when they begin paying the $1400.

when they begin the payment ,

t = 30 year - 5years

t= 25 years

$PV= 921.433 \begin {bmatrix} \dfrac{1 - (1 - \dfrac{0.078}{12})^{25*30}}{\dfrac{0.078}{12}} \end {bmatrix}$

PV = $121718.2714

C) In order to estimate how many payments of $1400 it will take to pay off the loan, we have:

$121718.2714 = \begin {bmatrix} \dfrac{1300 (1 - \dfrac{12.078}{12}))^{-nt}}{\dfrac{0.078}{12}} \end {bmatrix}$

$121718.2714 = 200000 \begin {bmatrix} (1 - \dfrac{12.078}{12}))^{-nt} \end {bmatrix}$

$\dfrac{121718.2714}{200000 } = \begin {bmatrix} (1 - \dfrac{12.078}{12}))^{-nt} \end {bmatrix}$

$0.60859 = \begin {bmatrix} (1 - \dfrac{12}{12.078}))^{nt} \end {bmatrix}$

$0.60859 = (0.006458)^{nt}$

$nt = \dfrac{0.60859}{0.006458}$

nt = 94.238 payments is required to pay off the loan.

How much interest will they save by paying the loan using the number of payments from part (c)?

The total amount of interest payed on $921.433 = 921.433 × 30(12) years

= 331715.88

The total amount paid using 921.433 and 1300 = (921.433 × 60 )+( 1300 + 94.238)

= 177795.38

The amount of interest saved = 331715.88 - 177795.38

The amount of interest saved = $153920.5

6 0

3 years ago

Solve for X. It trust in you guys ❤️

xenn [34]

Answer:

Step-by-step explanation:

Random

6 0

3 years ago

Let <img src="https://tex.z-dn.net/?f=%5Csf%20a%2Bb%2Ca-b%2Cab%2C%5Cdfrac%7Ba%7D%7Bb%7D" id="TexFormula1" title="\sf a+b,a-b,ab,

Black_prince [1.1K]

Answer:

171/40 or 4 11/40

Step-by-step explanation:

<h3>AP given</h3>

a + b, a - b, ab, a/b

6th term

<h3>Solution</h3>

Common difference

<u>Difference of first two</u>

d = (a -b) - (a + b) = -2b

<u>Difference of second two</u>

d= ab - (a - b)

<u>Difference of last two</u>

d = a/b - ab

<u>Now comparing d:</u>

-2b = ab - (a - b)
ab - a = - 3b
a(1 - b) = 3b
a = 3b/(1 - b)

and

a/b - ab = -2b
a(1/b - b) = -2b
a = 2b²/(b² - 1)

<u>Eliminating a:</u>

2b²/(b² - 1) = 3b/(1 - b)
2b/(b+1) = -3
2b = -3b - 3
5b = - 3
b = -3/5

<u>Finding a:</u>

a = 3b/(1 - b) =
3*(-3/5) *1/(1 - (-3/5)) =
-9/5*5/8 =
-9/8

<u>So the first term is:</u>

a + b = -3/5 - 9/8 = -24/40 - 45/40 = - 69/40

<u>Common difference:</u>

d = -2b = -2(-3/5) = 6/5

a₆ = a₁ + 5d =
-69/40 + 5*6/5 =
-69/40 + 240/40 =
171/40 = 4 11/40

8 0

3 years ago