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adoni [48]
3 years ago
8

I need in depth help answering ​

Mathematics
1 answer:
Volgvan3 years ago
8 0
What is the question
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In the alphabet, x comes before y. Use this fact to describe a method for remembering how to write ordered pairs.
Fofino [41]

Answer:

Step-by-step explanation:

so when remembering how to write ordered pairs, think of the monkey bars. you have to get there before you can climb up, x being walking to the monkey bars and y being climbing up them. Think of the steps to get to the monkey bars compared to the fact that x is before y. getting to the monkey bars comes before climbing them, is x (run) and climbing them would be y (rise), and not the other way around because like the question said; x comes before y.

I really hope this wasn't too confusing. I'm really sorry if it was!

Hope this helps! :)

3 0
3 years ago
Which equation is true for the value x = 15?
boyakko [2]
The third one because 2(15+5)=2(20)=40
4 0
3 years ago
Simplify: (4x - 6) - (5x + 1)​
marissa [1.9K]

Answer:

−x+−7

Step-by-step explanation:

Let's simplify step-by-step.

4x−6−(5x+1)

Distribute the Negative Sign:

=4x−6+−1(5x+1)

=4x+−6+−1(5x)+(−1)(1)

=4x+−6+−5x+−1

Combine Like Terms:

=4x+−6+−5x+−1

=(4x+−5x)+(−6+−1)

=−x+−7

3 0
2 years ago
12 × (3 + 2²) ÷ 2 - 10
Lynna [10]

Answer:

32

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A particle moves on a coordinate line with an acceleration at time t seconds of e^t/2 m/sec^2. At t=0 the particle is at the ori
castortr0y [4]
Hello,

A) a=e^ \frac{t}{2} \\\\

v(t)=\int\ a\ dt=\int\ e^ \frac{t}{2}\ dt=2*e^ \frac{t}{2}+C\\\\v(0)=-4\\
 2*e^ \frac{0}{2}+C=-4\\
 C=-6\\\\

\boxed{v(t)= 2*e^ \frac{0}{2}-6}\\\\





B)
2*e^ \frac{t}{2}-6=0\\\\

e^ \frac{t}{2}=3\\\\

t=2*ln(3)\approx{2,19722...}\\



C)

x(t)=\int_0^6(2*e^ \frac{t}{2}-6})\ dt=\left[4*e^ \frac{t}{2}-6t\right]_0^6\\\\ =e^3-36-4=4e^3-40\approx{40.3421...}\\\\



5 0
3 years ago
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