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3 years ago

What do solving absolute value equations and solving quadratic equations have in common?

Mathematics

2 answers:

NISA [10]3 years ago

6 0

Answer:

Step-by-step explanation:

Quadratic equations are equations that when rearranged using the 5 operations can yield a polynomial of degree 2 on one side of the equation and 0 on the other. There are 3 commonly taught methods for solving quadratic equations. These methods are factoring, completing the square, and the quadratic formula. These functions are most commonly used to model projectiles, disregarding air resistance.

When using the factoring method one attempts to write a degree 2 polynomial as the product of two degree 1 polynomials. This method works because if we multiply two degree one polynomials together we find

For example: When factoring , we want to find two number a, b whose product is 6 and sum to 5. The values of a and b we are looking for are 2 and 3.

The method of completing the square centers around using the five operations to replace the original equation with an equivalent equation of the form by taking advantage of the fact that

The absolute value function takes the value of a number, regardless of whether it is positive or negative. Some problems that the absolute value is useful for modeling include an object bouncing on the ground.

For example, , since we do not care about the negative sign.

Example: Solve

Solution: Since the absolute value does not care about whether a number is positive or negative, if then or . Then we can solve each equation individually to find that x = 1 or 5.

Dafna1 [17]3 years ago

5 0

Answer:

They often have more than one solution.

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Suppose you invest $950 at an annual interest rate of 6.5% compounded continuously. How much will you have in the account after

posledela

The correct answer is $1820.

The formula for continuously compounded interest is

A = Pe^(rt), where P is the amount of principal, r is the interest rate expressed as a decimal number, and t is the number of years. Using our information, we have:

A = 950*e^(0.065*10) = 1819.76 ≈ 1820

3 0

3 years ago

A boat captain can see a lighthouse on the shore which is 103ft in front of him. If the lighthouse is 22ft tall, at what angle o

elena-14-01-66 [18.8K]

Answer:

21°

Step-by-step explanation:

A boat captain, lighthouse and its base form a right triangle.

We need to find the angle opposite to 22 ft side:

tan x = 22/103
x = arctan (22/103)
x = 21°

Note, option D should read 21° not 11°

5 0

2 years ago

Please help: A box contains 5 yellow balls, 3 blue, and 1 red ball. Two balls are drawn at random. Find the probability that:

Y_Kistochka [10]

Answer:

a) 0.2778

b) 0.3611

c) 0.1389

d) 0.0833

Step-by-step explanation:

We have a total of 5 + 3 + 1 = 9 balls

a) First ball being yellow: we have 5 yellow balls, so P1 = 5/9

Second ball being yellow after one yellow was drawn: we have 4 yellows and 8 balls, so P2 = 4/8 = 1/2

Both yellows: P = P1 * P2 = 5/18 = 0.2778

b) Both blues:

P1 = 3/9 = 1/3

P2 = 2/8 = 1/4

P = P1 * P2 = 1/12 = 0.0833

Both yellows or both blues: 5/18 + 1/12 = 0.2778 + 0.0833 = 0.3611

c) First yellow: P1 = 5/9

Second red: P2 = 1/8

Pa = P1 * P2 = 5/72

First red: P3 = 1/9

Second yellow: P4 = 5/8

Pb = P3 * P4 = 5/72

P = Pa + Pb = 10/72 = 5/36 = 0.1389

d) First blue: P1 = 3/9 = 1/3

Second red: P2 = 1/8

Pa = P1 * P2 = 1/24

First red: P3 = 1/9

Second blue: P4 = 3/8

Pb = P3 * P4 = 1/24

P = Pa + Pb = 2/24 = 1/12 = 0.0833

8 0

3 years ago

What isbthe answer for tje pythagorean

nikdorinn [45]

The answer is going to be D

6 0

3 years ago

9. Water is added to two containers for 16 minutes. The equations below model the ounces of

Vladimir [108]

The two containers hold 328 ounces at the they hold same amount of water.

Step-by-step explanation:

The equations below model the ounces of water, y, in each container after x minutes.

$y = 16x + 104$

$y = -2x^{2} +40x+160$

At the time after the start when the containers hold the same amount of water, the two equations must be equal.

⇒ $16 x + 104 = -2x^{2} + 40 x + 160$

The first step is to divide everything by 2 to make it simplified.

⇒ $8 x + 52 = - x^2 +20 x + 80$

Now put everything on the left .

$x^2 + 8 x - 20 x + 52 - 80 = 0$

Add the like terms together to further reduce the equation

$x^2 - 12 x - 28 = 0$

Factorizing the equation to find the roots of the equation.

Here, b = -12 and c = -28

where,

b is the sum of the roots ⇒ -14 + 2 = -12
c is the product of the roots ⇒ -14 × 2 = -28

Therefore, (x-14) (x+2) = 0
The solution is x = -2 or x = 14

Take x = 14 and substitute in any of the given two equations,

⇒ $y = 16(14) + 104$

⇒ $y =224+104$

⇒ 328 ounces

∴ The two containers hold 328 ounces at the they hold same amount of water.

5 0

3 years ago