Answer:
Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.
Let Q be the point onthe circle in which, tangent make 90° with radius at Q.
PQ = 8 and OQ = 6
we get a right angled triangle PQO right angled at Q.
so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==
therefore OP =10cm
we need nearest point from P, which is PA
PA = OP - OA= 10 -6=4cm
Answer:
Step-by-step explanation:
we know that
The <u>distance formula</u> is derived by creating a triangle and using the Pythagorean theorem to find the length of the hypotenuse. The hypotenuse of the triangle is the distance between the two points
The formula to calculate the distance between two points is equal to
we have
A(1, 1) and B(7, −7)
Let
(x1,y1)=A(1, 1)
(x2,y2)=B(7, −7)
substitute the given values in the formula
The value of 47-36÷3(5+7-3²) is 11.
Answer:
Total = 2,400 * (1 + (.083/4))^4*5
Total = 2,400 * (1.02075)^20
Total = 2,400 * 1.5079528829
Total = 3,619.09
Step-by-step explanation:
Following with the extra hint that x = 82.03 m
There are 2 ways to approach the question, but although I prefer to group up x first before plugging value, having that -0.05x^2 to group up is too annoying:
Plug x = 82.03
=> Y = -0.05*(82.03^2) + 4.5*82.03 - 6.5
= -336.446045 + 369.135 - 6.5
= 26.188955 m
Please take the time and understand the answer instead of just looking at the final result.
Also I know the number is very long, but that's the question's fault. <span>¯\_(ツ)_/¯</span>
