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RideAnS [48]
3 years ago
5

Solve for P. S=A+1/2PL

Mathematics
1 answer:
Dovator [93]3 years ago
5 0

9514 1404 393

Answer:

  (b)  P = 2(S -A) ÷ L

Step-by-step explanation:

Undo what is done to P.

  S=A+\dfrac{1}{2}PL\qquad\text{given}\\\\S-A = \dfrac{1}{2}PL\qquad\text{subtract $A$}\\\\\dfrac{2}{L}(S-A)=P \qquad\text{multiply by $\dfrac{2}{L}$}\\\\\boxed{P=\dfrac{2(S-A)}{L}}

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