3 years ago

Solve for P. S=A+1/2PL

Mathematics

1 answer:

Dovator [93]3 years ago

5 0

9514 1404 393

Answer:

(b) P = 2(S -A) ÷ L

Step-by-step explanation:

Undo what is done to P.

$S=A+\dfrac{1}{2}PL\qquad\text{given}\\\\S-A = \dfrac{1}{2}PL\qquad\text{subtract $A$}\\\\\dfrac{2}{L}(S-A)=P \qquad\text{multiply by $\dfrac{2}{L}$}\\\\\boxed{P=\dfrac{2(S-A)}{L}}$

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