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3 years ago

The perimeter of a rectangular sandbox is 34 feet if the length of the sandbox is 8 feet what is the width of the sandbox

2 answers:

8 0

L= length
W= width

Perimeter= 2L + 2W

substitute the known numbers
34 ft= 2(8 ft) + 2W

34= 16 + 2W
subtract 16 from both sides

18= 2W
divide both sides by 2

9 ft= W

ANSWER: The width is 9 feet.

Hope this helps! :)

Allisa [31]3 years ago

6 0

The perimeter of a rectangular is:
P=2(l+w)
P=perimeter
l=length
w=width

P=2(l+w)
34=2(8+w)
34=16+w
w=18

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We have been given two vectors $\vec{a}$ and $\vec{b}$ , we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

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To learn more about scalar and vector projection visit:brainly.com/question/21925479

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Answer:

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Step-by-step explanation:

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