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Nutka1998 [239]
3 years ago
14

The perimeter of a rectangular sandbox is 34 feet if the length of the sandbox is 8 feet what is the width of the sandbox

Mathematics
2 answers:
MrRa [10]3 years ago
8 0
L= length
W= width

Perimeter= 2L + 2W

substitute the known numbers
34 ft= 2(8 ft) + 2W

34= 16 + 2W
subtract 16 from both sides

18= 2W
divide both sides by 2

9 ft= W


ANSWER: The width is 9 feet.

Hope this helps! :)
Allisa [31]3 years ago
6 0
The perimeter of a rectangular is:
P=2(l+w)
P=perimeter
l=length
w=width

P=2(l+w)
34=2(8+w)
34=16+w
w=18
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\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})

We have been given two vectors $\vec{a}$ and $\vec{b}$, we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

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$$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

#SPJ4

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1 year ago
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Answer:

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Step-by-step explanation:

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