The perimeter of a rectangular sandbox is 34 feet if the length of the sandbox is 8 feet what is the width of the sandbox
2 answers:
L= length W= width Perimeter= 2L + 2W substitute the known numbers 34 ft= 2(8 ft) + 2W 34= 16 + 2W subtract 16 from both sides 18= 2W divide both sides by 2 9 ft= W ANSWER: The width is 9 feet. Hope this helps! :)
The perimeter of a rectangular is: P=2(l+w) P=perimeter l=length w=width P=2(l+w) 34=2(8+w) 34=16+w w=18
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Answer:
y = 5x + 4
Step-by-step explanation:
5x - y = -4
5x - 5x - y = -4 - 5x
-y = -5x -4
y = 5x + 4
No, because an equilateral triangle is also equiangular so all sides must be 60° (60+60+60=180) and an obtuse angle is more than 90° so the triangle would not be equilateral. Hope I Helped (:
Here is the answer, I think.
Answer: 1/4
Step-by-step explanation: If you divide both 6 and 24 by 6 you get 6/6=1 and 24/6=4.
The distance between -2.6 and -2.1 is .5