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Marta_Voda [28]
3 years ago
5

What are the solutions of the equation x2-30=x

Mathematics
1 answer:
xeze [42]3 years ago
3 0

Answer:

x = 6 or x = -5

Step-by-step explanation:

x^2 - 30 = x

x^2 - x - 30 = 0

(x - 6)(x + 5) = 0

x - 6 = 0 or x + 5 = 0

x = 6 or x = -5

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A body moves s metres in a time t seconds so that s = t3 – 3t2 + 8. Find:
Lady bird [3.3K]

Using derivatives, it is found that:

i) v(t) = 3t^2 - 6t

ii) 9 m/s.

iii) a(t) = 6t - 6

iv) 6 m/s².

v) 1 second.

<h3>What is the role of derivatives in the relation between acceleration, velocity and position?</h3>
  • The velocity is the derivative of the position.
  • The acceleration is the derivative of the velocity.

In this problem, the position is:

s(t) = t^3 - 3t^2 + 8

item i:

Velocity is the <u>derivative of the position</u>, hence:

v(t) = 3t^2 - 6t

Item ii:

v(3) = 3(3)^2 - 6(3) = 27 - 18 = 9

The speed is of 9 m/s.

Item iii:

Derivative of the velocity, hence:

a(t) = 6t - 6

Item iv:

a(2) = 6(2) - 6 = 6

The acceleration is of 6 m/s².

Item v:

t for which a(t) = 0, hence:

6t - 6 = 0

6t = 6

t = \frac{6}{6}

t = 1

Hence 1 second.

You can learn more about derivatives at brainly.com/question/14800626

7 0
2 years ago
X- 18 = 0<br> Number of real number solutions
Neko [114]

Answer:

X= 18

Step-by-step explanation:

18-18=0

x=18

5 0
3 years ago
Read 2 more answers
In a toy factory 200 wooden soils cylinders 7 cm long and 35 mm in diameter have to be painted. What is the total surface area i
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By applying 2×pie×radius (radius+height)
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6 0
3 years ago
Match each expression in the left column with the correct product in the right column.
lesya692 [45]

Answer:

-6

-6i

6i

6

Step-by-step explanation:

1) √4 . √-3 . √-3

$ \sqrt{4} = 2 $

$ \sqrt{-3} . \sqrt{-3} = (\sqrt{-3})^2 $

$ \sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 = $ -6

2) √-4 . √-3 . √-3

$ \sqrt{-4} = 2i $ .

Therefore, $ \sqrt{-4} . \sqrt{-3} . \sqrt{-3} = 2. \sqrt{-1}  \times -3 = 2i \times (-3) =  $ - 6i

3) √4 . √3 . √-3

$ \sqrt{4} = 2 $

$ \sqrt{3} . \sqrt{-3} = (\sqrt{3})^2 . \sqrt{-1} $

$ \implies 2 \times 3i = $ 6i

4) √4 . √3 . √3

$ \sqrt{4} = 2 $

$ \sqrt{3} . \sqrt{3} = (\sqrt{3})^2  = 3 $

Therefore, √4 . √3 . √3 = 2 . 3 = 6

5 0
3 years ago
ou live in the building on the left in the drawing, and a friend lives in the other building. the two of you are having a discus
Alenkinab [10]

Answer:

1.3

Friend is wrong

Step-by-step explanation:

Given:

friend's claim: height of his building is more than 1.50 times the height of yours

line of sight to the top edge of the other building makes an angle of 21° above the horizontal

line of sight to the base of the other building makes an angle of 52° below the horizontal

Solution:

Let A be the height of your building is A

Let B+A his building is B higher than yours.

Let the distance between the buildings is x.  

then

tan 52 = A/x

tan 21 = B/x  

A/B = tan 52 / tan 21

      =  1.27994 / 0.38386

A/B = 3.33

(A + B) / A = 1.5 0

A/A + B/A = 1.50

1 + B/A = 1.50

B/A is basically (B/x) / (A/x)

So

1+ 3.33 / 3.33

= 4.33/3.33

= 1.3

Since 1.3 is not equal to 1.5

Hence the friend's claim is wrong.

5 0
3 years ago
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