All categories

3 years ago

Please help whatbis the answer

Mathematics

1 answer:

Irina-Kira [14]3 years ago

6 0

It’s the last one, cause Susan charges 20 per photo

You might be interested in

$29,000; 4% decrease

Sveta_85 [38]

Answer:

$27,840 is the correct answer

Step-by-step explanation:

hope this helps!

7 0

3 years ago

Read 2 more answers

1) Slope =-1, y-intercept = 0

Dima020 [189]

Answer:

1. C 2.D 3.D 4.A

Step-by-step explanation:

The first one would be C because the slope is -1, which can also be -x and the y-intercept is 0, meaning you don't need to add or subtract anything.

The second one is D because the slope is -3, meaning it's -3x, and the y-intercept is positive, meaning you add 5.

The third one is D because the slope is 5/4, which is 5/4x and the y-intercept is positive 3, meaning you add 3.

And the fourth one is A because there is no slope, so y would just equal 3.

6 0

3 years ago

12x + 3x = ___? Please explain

Paladinen [302]

Answer:15x

Step-by-step explanation:you add 12 + 3 which equals 15 and then you just carry the x over

6 0

3 years ago

The given line segment has a midpoint at (3, 1).

Katena32 [7]

Answer:

$y=\frac{1}{3}x$

Step-by-step explanation:

The given line segment has a midpoint at (3, 1) and goes through (2, 4), (3, 1), and (4, -2). We can use any two of the three points to calculate the equation of the line. Let us use the points (2, 4) and (4, -2)

Therefore the line goes through (2, 4) and (4, -2). The equation of a line passing through $(x_1,y_1)\ and\ (x_2,y_2)$ is:

$\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}$ .

Therefore the line passing through (2, 4) and (4, -2) has an equation:

$\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}\\\frac{y-4}{x-2}=\frac{-2-4}{4-2}\\\frac{y-4}{x-2}=\frac{-6}{2}\\y-4=x-2(-3)\\y-4=-3x+6\\y=-3x+10$

Comparing with the general equation of line: y = mx + c, the slope (m) = -3 and the intercept on the y axis (c) = 10

Two lines are said to be perpendicular if the product of their slope is -1. If the slope of line one is m1 and the slope of line 2 = m2, then the two lines are perpendicular if:

$m_1m_2=-1$ .

Therefore The slope (m2) of the perpendicular bisector of y = -3x + 10 is:

$m_1m_2=-1\\-3m_2=-1\\m_2=\frac{1}{3}$

Since it is the perpendicular bisector of the given line segment, it passes through the midpoint (3, 1). The equation of the perpendicular bisector is:

$\frac{y-y_1}{x-x_1}=m\\\frac{y-1}{x-3}=\frac{1}{3}\\ y-1= \frac{1}{3}(x-3)\\ y-1=\frac{1}{3}x-1\\y=\frac{1}{3}x$