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vovikov84 [41]
4 years ago
11

Identify the area of the trapezoid. Please help!

Mathematics
2 answers:
balandron [24]4 years ago
5 0
The answer for this one is the last one
barxatty [35]4 years ago
4 0

Answer:

94.5x cm^2

Step-by-step explanation:

!/2h(b1 +b2) = 1/2(7)(12x +15x) = 3.5(27x) = 94.5

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Solve -2x^2 + 10x + 9 =0 by using completing the squares and give u r answer to two decimal places
adell [148]
<span>-2x^2 + 10x + 9 =0
multiply whole equation by -1
2x^2  -10x -9 =0

(sqrt2x)^2  -2(sqrt2x)(5/</span>sqrt2) -9=0
add (5/sqrt2)^2 on both sides
(sqrt2x)^2  -2(sqrt2x)(5/sqrt2) + (5/sqrt2)^2-9=(5/sqrt2)^2

a^2-2ab+b^2=(a-b)^2
(sqrt2x  -  5/sqrt2)^2=(5/sqrt2)^2+9

(sqrt2x  -  5/sqrt2)^2=21.5

taking squareroot on both sides

sqrt2x  -  5/sqrt2 = +-4.64
so
sqrt2x  -  5/sqrt2 = +4.64       or         sqrt2x  -  5/sqrt2 = -4.64
sqrt2x = 4.64 +  5/sqrt2                     sqrt2x = -4.64 +  5/sqrt2
sqrt2x =8.18                                         sqrt2x = -1.1045
x=8.18/sqrt2                                        x= -1.1045/sqrt2
x=5.78                                                 x=-0.781
3 0
3 years ago
Read 2 more answers
Please answer quickly
Juliette [100K]

Answer:

Step-by-step explanation:

4^3 * 4^4 = 4^(3+4) = 4^7

4^7/4^9 = 4^(7-9)

= 4^-2 = 1/4^2

6 0
3 years ago
Which equation is a point slope form equation for line AB ?
Stells [14]

Answer:

y -5 = (3/4)(x -6)

Step-by-step explanation:

Between the two points, the line has a rise of 6 and a run of 8. Thus, the slope is ...

... m = rise/run = 6/8 = 3/4

The point-slope form of the equation of a line with slope m through point (h, k) is ...

... y - k = m(x - h)

For point B, (h, k) = (6, 5), so filling in the values gives ...

... y - 5 = (3/4)(x - 6)

3 0
3 years ago
Find the total surface area of these solids
12345 [234]
<h2>Step-by-step explanation:</h2><h3>We firstly find the surface area of only one face of the cube:</h3><h3>Sa=a²</h3><h3>Sa=1.2²cm</h3><h3>Sa=1.44cm²</h3>

<h2>Since the cube has 6 faces we multiply the surface area of one face(144cm²) with 6</h2>

Area(cube)=1.44cm²*6

=8.64cm²

<h2>Same thing with the prism but we have to find the area of one of his triangle face and rectangle face</h2>

S(triangle)=5mm*4mm*1/2

=10mm²

S(rectangle)=7mm*5mm=35mm²

<h2>The prism has 2 triangle faces and three rectangle faces so we multiply the area by those numbers and then we add those together to get the final area</h2>

S=10mm²*2+35mm²*3

S=20+105

S=125mm²

<h3><em>Hope this helped..</em></h3><h3 /><h3><em>Hope this helped..Brainliest pls..</em></h3>
4 0
3 years ago
Carry out three steps of the Bisection Method for f(x)=3x−x4 as follows: (a) Show that f(x) has a zero in [1,2]. (b) Determine w
ELEN [110]

Answer:

a) There's a zero between [1,2]

b) There's a zero between [1.5,2]

c) There's a zero between  [1.5,1.75].

Step-by-step explanation:

We have f(x)=3^x-x^4

A)We need to show that f(x) has a zero in the interval [1, 2]. We have to see if the function f is continuous with f(1) and f(2).

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(2)=3^2-(2)^4=9-16=(-7)

We can see that f(1) and f(2) have opposite signs. And f(1)>f(2) and the function is continuous, this means that exists a real number c between the interval [1,2] where f(c)=0.

B)We have to repeat the same steps of A)

For the subinterval [1,1.5]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1) and f(1.5) have the same signs, this means there's no zero in the subinterval [1,1.5].

For the subinterval [1.5,2]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.5) and f(2) have opposite signs, this means there's a zero between the subinterval [1.5,2].

C)We have to repeat the same steps of A)

For the subinterval [1,1.25]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5

f(1) and f(1.25) have the same signs, this means there's no zero in the subinterval [1,1.25].

For the subinterval [1.25,1.5]:

f(x)=3^x-x^4\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1.25) and f(1.5) have the same signs, this means there's no zero in the subinterval [1.25,1.5].

For the subinterval [1.5,1.75]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)

f(1.5) and f(1.75) have opposite signs, this means there's a zero between the subinterval [1.5,1.75].

For the subinterval [1.75,2]:

f(x)=3^x-x^4\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.75) and f(2) have the same signs, this means there isn't a zero between the subinterval [1.75,2].

The graph of the function shows that the answers are correct.

6 0
3 years ago
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