Perimeter of rectangle=66
length of rectangle=L
width of rectangle=w
P of a rect.= 2(length)+ 2(width)
66= 2L+2w
if the length is 7in more than the width, then
L=7+w
Now we will substitute 7+w in for L. Here is our new equation:
66=2(7+w) + 2w
Solve for w
66=14+2w+2w
66=14+4w
52=4w
w=13
L=7+13, so L=20
I hooe this is explained well enough
- 4 w - 4 = - 24
- 4w = - 20
w = 5
Answer:
w = 8
Step-by-step explanation:
–9 = –3(w − 5)
-3(w - 5) = -9
w - 5 = 3
w = 5 + 3
w = 8
