Answer:
(0,0) doesn’t show a rate of 12 messages per hour
I’m confused about the rest please elaborate
Step-by-step explanation:
Answer:
Step-by-step explanation:
This is a problem of SETS.
Start by listing out important data:
1. Total that said F = 55
2. Total that said P = 51
3. Total that said O = 61
4. F only = 9
5. F ∩ P ∩ O = 26 [NOTE: If you were to draw a Venn Diagram, 26 would be in the innermost circle because it comprises all three categories]
6. F ∩ P = 31
7. P only = 8
8. Students that said none of the 3 reasons = 4
QUESTIONS
1. How many said O and P? In other words, find the intersect of O and P. Find O ∩ P
2. How many said either F or O? [Answer to be gotten using a venn diagram] Find F ∪ P which translates to "F union P"
3. How many said F without saying P? [Answer to be gotten from the venn diagram as well]
4. How many students in total were surveyed? [HINT: Remember to include the 4 students that had none of the three options]
Answer:
5:55
Step-by-step explanation:
but I depends when u left the mall then stuck in traffic, because it said u reach at the mall
sorry if its wrong
Answer:
f(x) = 1 + x + (x²/2!) + (x³/3!) + ....... = Σ (xⁿ/n!) (Summation from n = 0 to n = ∞)
Step-by-step explanation:
f(x) = eˣ
Expand using first Taylor Polynomial based around b = 0
The Taylor's expansion based around any point b, is given by the infinite series
f(x) = f(b) + xf'(b) + (x²/2!)f"(b) + (x³/3!)f'''(b) + ....= Σ (xⁿfⁿ(b)/n!) (Summation from n = 0 to n = ∞)
Note: f'(x) = (df/dx)
So, expanding f(x) = eˣ based at b=0
f'(x) = eˣ
f"(x) = eˣ
fⁿ(x) = eˣ
And e⁰ = 1
f(x) = 1 + x + (x²/2!) + (x³/3!) + ....... = Σ (xⁿ/n!) (Summation from n = 0 to n = ∞)
