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alexira [117]
2 years ago
10

M is the midpoint of the segment. Find the length of XM.

Mathematics
1 answer:
Eduardwww [97]2 years ago
6 0

Answer:

Step-by-step explanation:

4x+3=3x+5

x+3=5

x=2

Subsitute: 4x+3=11

XM=11

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Is angle angle side right yall?
sashaice [31]

Answer:

SAS since only one angle, the right angles are congruent on them. Two sides are marked congruent to each of their corresponding sides so it is side angle side.

Step-by-step explanation:

6 0
2 years ago
Rewrite the expression in the form... (PLZ HELP QUICK I'LL GIVE BRAINLIEST)
ivanzaharov [21]

Answer: 3*z^\frac{2}{9}

Step-by-step explanation:

The exponent 1/3 is the same thing as cube rooting the expression.

\sqrt[3]{27\sqrt[3]{z^2} }

3*z^{2/9}

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4 0
3 years ago
When the function below is graphed, how many x-intercepts does it have?y = 4x2 - 12x + 9?
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Only x-intercept because if you want to know about x-intercepts so y will be zero (y=0)
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7 0
3 years ago
Read 2 more answers
Which expression is equivalent to 3x + 2.5(4x + 2)?
Alex787 [66]

Answer:

I think its B

Step-by-step explanation:

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6 0
2 years ago
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Better Products, Inc., manufactures three products on two machines. In a typical week, 40 hours are available on each machine. T
Kaylis [27]

Answer:

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

Step-by-step explanation:

                                Profit $    mach. 1      mach. 2

Product 1     ( x₁ )       30             0.5              1

Product 2    ( x₂ )       50             2                  1

Product 3    ( x₃ )       20             0.75             0.5

Machinne 1 require  2 operators

Machine   2 require  1  operator

Amaximum of  100 hours of labor available

Then Objective Function:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Constraints:

1.-Machine 1 hours available  40

In machine 1    L-H  we will need

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

2.-Machine 2   hours available  40

1*x₁  +  1*x₂   + 0.5*x₃   ≤  40

3.-Labor-hours available   100

Machine 1     2*( 0.5*x₁ +  2*x₂  +  0.75*x₃ )

Machine  2       x₁   +   x₂   +  0.5*x₃  

Total labor-hours   :  

2*x₁  +  5*x₂  +  2*x₃  ≤  100

4.- Production requirement:

x₁  ≤  0.5 *( x₁ +  x₂  +  x₃ )     or   0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

5.-Production requirement:

x₃  ≥  0,2 * ( x₁  +  x₂   +  x₃ )  or    -0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

General constraints:

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

The model is:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Subject to:

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

1*x₁  +  1*x₂   + 0.5*x₃       ≤  40

2*x₁  +  5*x₂  +  2*x₃        ≤  100

0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

-0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

After 6 iterations with the help of the on-line solver AtomZmaths we find

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

6 0
3 years ago
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