Please help im gonna cry substitute these simultaneous a+2p=4 x-2y=6

What is the value of x to the nearest tenth? A) 3.3 B) 9.5 C) 8.0 D) 4.7

Alisiya [41]

Answer:

D) 4.7

Step-by-step explanation:

this perpendicular connection with the circle center cuts this intersecting line in half, which is therefore on both sides of x 6.5 long.

I assume 16 is the diameter, so the radius is 8.

therefore, x is one side of the right-angled triangle of

radius

x

half of the intersecting line

Pythagoras

8² = x² + (6.5)²

64 = x² + 42.25

21.75 = x²

x = 4.7

6 0

3 years ago

A man standing 13 feet from the base of a lamppost casts a shadow 5 feet long. if the man is 6 feet tall and walks away from the

Umnica [9.8K]

10Find the height of the flag pole in m.1120Find d if b = 6, e = 15, and a = 8.8.25Find a if b = 11, e = 8, and d = 6.151.62.25A 3.2 m ladder is leaning against a wall with its foot 1.5 m from the wall. How far is a second ladder from the wall if it is 4.8 m long and parallel to the first ladder?20A person whose eye height is 1.6 m stands 0.8 m from a mirror. If the mirror is 10 m from a wall when the person sees the top of the wall, how tall is the wall?32.5A person whose eye height is 1.5 m stands 0.3 m from a mirror and sees the top of a building in the mirror. If the mirror is 6.5 m from the wall, how tall is the wall?8.4A person whose eye height is 1.2 m stands 0.4 m from a mirror. If the mirror is 2.8 m from the wall when the person sees the top of the wall, how tall is the wall?12.5A building casts a shadow 37.5 m long. If a metre stick casts a shadow 3 m long at the same time and location, how tall is the building?30A man is 6 feet tall, his shadow is 3.5 feet. He is standing next to a flagpole with a shadow of 17.5 feet. How tall is the flagpole?0.5x/10 = 5/100

7 0

3 years ago

Which of the following shows the polynomial below written in descending order?

Vladimir79 [104]

Answer:

A. 4x¹² + 9x⁷ + 3x³ -x

Step-by-step explanation:

Hi!

==================================================================

To write a polynomial in descending order, we write the terms with higher degrees, or exponents, first.

3x³ + 9x⁷ -x + 4x¹²

4x¹² has the highest degree, so it is written as the first term.

⇒4x¹²

9x⁷ has the next highest degree, so it is written next.

⇒4x¹² + 9x⁷

3x³ has the next highest degree, so it is written next.

⇒4x¹² + 9x⁷ + 3x³

-x has the lowest degree, so it is written last.

⇒4x¹² + 9x⁷ + 3x³ -x

4x¹² + 9x⁷ + 3x³ -x

==================================================================

Hope I Helped, Feel free to ask any questions to clarify :)

Have a great day!

-Aadi x

8 0

3 years ago

Two different radioactive isotopes decay to 10% of their respective original amounts. Isotope A does this in 33 days, while isot

Andrews [41]

Answer:

The approximate difference in the half-lives of the isotopes is 66 days.

Step-by-step explanation:

The decay of an isotope is represented by the following differential equation:

$\frac{dm}{dt} = -\frac{t}{\tau}$

Where:

$m$ - Current mass of the isotope, measured in kilograms.

$t$ - Time, measured in days.

$\tau$ - Time constant, measured in days.

The solution of the differential equation is:

$m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$

Where $m_{o}$ is the initial mass of the isotope, measure in kilograms.

Now, the time constant is cleared:

$\ln \frac{m(t)}{m_{o}} = -\frac{t}{\tau}$

$\tau = -\frac{t}{\ln \frac{m(t)}{m_{o}} }$

The half-life of a isotope ( $t_{1/2}$ ) as a function of time constant is:

$t_{1/2} = \tau \cdot \ln2$

$t_{1/2} = -\left(\frac{t}{\ln\frac{m(t)}{m_{o}} }\right) \cdot \ln 2$

The half-life difference between isotope B and isotope A is:

$\Delta t_{1/2} = \left| -\left(\frac{t_{A}}{\ln \frac{m_{A}(t)}{m_{o,A}} } \right)\cdot \ln 2+\left(\frac{t_{B}}{\ln \frac{m_{B}(t)}{m_{o,B}} } \right)\cdot \ln 2\right|$

If $\frac{m_{A}(t)}{m_{o,A}} = \frac{m_{B}(t)}{m_{o,B}} = 0.9$ , $t_{A} = 33\,days$ and $t_{B} = 43\,days$ , the difference in the half-lives of the isotopes is:

$\Delta t_{1/2} = \left|-\left(\frac{33\,days}{\ln 0.90} \right)\cdot \ln 2 + \left(\frac{43\,days}{\ln 0.90} \right)\cdot \ln 2\right|$

$\Delta t_{1/2} \approx 65.788\,days$

The approximate difference in the half-lives of the isotopes is 66 days.

4 0

3 years ago

Read 2 more answers

Donna opens a certificate of deposit (CD) with $2,000. The bank offers a 3% interest rate. If the account compounds quarterly, w

SSSSS [86.1K]

1) Quaterly interes = 3% / 4 = 0.03 / 4

2) Values:

after 1 quarter: 2000 (1 + 0.03/4)

after 2 quarters: 2000 (1 + 0.03/4)^2

after 3 quarters: 2000 (1 + 0.03/40^4

after 4 quarters = 2000 (1 + 0.03/4)^4

You could have used the future value formula directly:

A = C * (1 + r/n) ^ n*t

where r = 3% = 0.03

n = number of periods in a year: 4

t = number of years = 1

C = initial investment = 20000

=> A = 2000 (1 + 0.03/4)^4

Answer: option D. A = 2000 ( 1 + 0.03 /4) 4

8 0

4 years ago