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3 years ago

14

What is the value represented by the letter A on the box plot of the data?

1 answer:

Vika [28.1K]3 years ago

3 0

The answer is 10.

the part furthest to the left always represents the least number.

:)

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What is a unit rate????????????????????????????????????????????

Ksivusya [100]

The rate of a unit per one. So for example 40miles/1hour. Hope it helped. :)

5 0

3 years ago

Kenji buys 3 yards of fabric 7.47.Then he realizes that he needs 2 more yards. How much will extra fabric costs?

Tom [10]

= 4.98
each yard of fabric costs 2.49

4 0

3 years ago

10 less than the quotient of g and 3

Phantasy [73]

(g/3)-10 or g÷3-10

This is g divided by 3 minus 10

7 0

3 years ago

In 2000 there were about 2,172,000 farms in the United States. Twenty -four thousand of the farms were in South Carolina. What p

Shalnov [3]

The amount of South Carolina Farms in the US is 24000/2172000
→ 24 000 ÷ 2 172 000 = 0.1104972
→ To convert into a percentage: 0.1104972 x 100 = 11.04972
→ Round 11.04972 to 11 (nearest whole percent)

∴ The percentage of farms in South Carolina is 11%

4 0

3 years ago

Save me the headache

maxonik [38]

$(9\sin2x+9\cos2x)^2=81$

Taking the square root of both sides gives two possible cases,

$9\sin2x+9\cos2x=9\implies\sin2x+\cos2x=1$

or

$9\sin2x+9\cos2x=-9\implies\sin2x+\cos2x=-1$

Recall that

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

If $\alpha=2x$ and $\beta=\dfrac\pi4$ , we have

$\sin\left(2x+\dfrac\pi4\right)=\dfrac{\sin2x+\cos2x}{\sqrt2}$

so in the equations above, we can write

$\sin2x+\cos2x=\sqrt2\sin\left(2x+\dfrac\pi4\right)=\pm1$

Then in the first case,

$\sqrt2\sin\left(2x+\dfrac\pi4\right)=1\implies\sin\left(2x+\dfrac\pi4\right)=\dfrac1{\sqrt2}$

$\implies2x+\dfrac\pi4=\dfrac\pi4+2n\pi\text{ or }\dfrac{3\pi}4+2n\pi$

(where $n$ is any integer)

$\implies2x=2n\pi\text{ or }\dfrac\pi2+2n\pi$

$\implies x=n\pi\text{ or }\dfrac\pi4+n\pi$

and in the second,

$\sqrt2\sin\left(2x+\dfrac\pi4\right)=-1\implies\sin\left(2x+\dfrac\pi4\right)=-\dfrac1{\sqrt2}$

$\implies2x+\dfrac\pi4=-\dfrac\pi4+2n\pi\text{ or }-\dfrac{3\pi}4+2n\pi$

$\implies2x=-\dfrac\pi2+2n\pi\text{ or }-\pi+2n\pi$

$\implies x=-\dfrac\pi4+n\pi\text{ or }-\dfrac\pi2+n\pi$

Then the solutions that fall in the interval $[0,2\pi)$ are

$x=0,\dfrac\pi4,\dfrac\pi2,\dfrac{3\pi}4,\pi,\dfrac{5\pi}4,\dfrac{3\pi}2,\dfrac{7\pi}4$

5 0

3 years ago

Read 2 more answers