3 years ago

- 5,6,7 pls help. Factorise this pls

1 answer:

5 0

Answer:

Step-by-step explanation:

5. -3x^(2)+3xy-4xz

If you factor = -x(3x-3y+4z)

x^yz+xy^2z+xyz^2

xyz(x+y+z)

x^2y-xy^2+x^2y^2

xy(x-y+xy)

6. 14a^2-28a^2b^2+21a^4

-7a^2(4b^2-3a^2-2)

7. a^4b-6a^2b^2+3ab^3

ab(a^3-6ab+3b^2)

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For this, I'll be using the substitution method. Since y = 1/3x - 6, replace the y variable in the first equation with 1/3x - 6 and solve for x:

$x+3(\frac{1}{3}x-6)=-12\\ x+x-18=-12\\ 2x-18=-12\\ 2x=6\\ x=3$

Now that we have the value of x, plug it into either equation to solve for y:

$3+3y=-12\\ 3y=-15\\ y=-5\\ \\ y=\frac{1}{3}*3-6\\ y=1-6\\ y=-5$

<h3><u>In short, the solution to this equation is (3,-5).</u></h3>

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