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3 years ago

Help please..........

Mathematics

1 answer:

Yuri [45]3 years ago

8 0

Answer:

Step-by-step explanation:

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A DVD player is on sale at a 25% discount. Find the sale price of the DVD player if it normally sells for $299.

s2008m [1.1K]

$224.25 Mark me brainliest please!

4 0

2 years ago

Read 2 more answers

6. What impact does the 5 have in the following equation. y = 5(x+2)^2 +

yulyashka [42]

Answer:

B. It makes the graph really narrow.

Step-by-step explanation:

$\displaystyle Y = A[X - H]^2 + K$

In the Vertex Formula, any fraction you store in for A will result in a vertical shrink, widening the graph, whereas any whole number you store in for A will result in a vertical stretch, narrowing the graph.

I am joyous to assist you at any time.

4 0

2 years ago

CALCULUS: For an object whose velocity in ft/sec is given by v(t) = sin(t), what is its distance, in feet, travelled on the inte

rodikova [14]

The linked answer is wrong because that integral gives you the net displacement of the object, not the total distance.

To get the distance, you have to integrate the speed (as opposed to velocity), which involves integrating the absolute value of the velocity function.

$\mathrm{distance} = \displaystyle\int_1^5 |\sin(t)| \,\mathrm dt$

By definition of absolute value,

$|\sin(t)|=\begin{cases}\sin(t)&\text{for }\sin(t)\ge0\\-\sin(t)&\text{for }\sin(t)$

Over this particular integration interval,

• sin(t ) ≥ 0 for 1 ≤ t < π, and

• sin(t ) < 0 for π < t ≤ 5

so you end up splitting the integral at t = π as

$\mathrm{distance} = \displaystyle\int_1^\pi \sin(t)\,\mathrm dt + \int_\pi^5 (-\sin(t))\,\mathrm dt$

Now compute the distance:

$\mathrm{distance} = -\cos(t)\bigg|_1^\pi + \cos(t)\bigg|_\pi^5$

$\mathrm{distance} = -(\cos(\pi) - \cos(1)) + (\cos(5) - \cos(\pi))$

$\mathrm{distance} = -2\cos(\pi) + \cos(1) + \cos(5) \approx 2.82$

making B the correct answer.

7 0

2 years ago

PLEASE HELP GEOMETRY QUESTION

V125BC [204]

Answer: D

Step-by-step explanation:

6 0

2 years ago

Find the linear approximation of f(x)=lnx at x=1 and use it to estimate ln(1.38).

RideAnS [48]

$\bf f(x)=y=ln(x)\qquad 
\begin{cases}
x=1\\
y=ln(1)\to y=0
\end{cases}\\\\
-----------------------------\\\\
\left. \cfrac{dy}{dx}=\cfrac{1}{x} \right|_{x=1}\implies 1\impliedby m
\\\\\\
\textit{now, we know that }
\begin{cases}
x=1\\
y=0\\
m=1
\end{cases}\implies y-0=1(x-1)\implies y=x-1$

now, you're asked to use it when ln(1.38), which is just another way of saying x = 1.38

so set x = 1.38 and see what "y" is

5 0

3 years ago