Answer:
Yes, is should work
Explanation:
USB is widely adopted and supports both forward and backward compatibility. The USB 3.0 printer should work with the USB 2.0 computer. However, having a connection like this, the printer will only be able to work at the speeds of the computer’s USB 2.0. By default, USB is built to allow transfer speeds improvement with upgrades from previous generations while still maintaining compatibility between devices that are supported by them.
Answer:
Explanation:
d(x) = -2x - 6
to find the inverse of a function, you need to follow these steps:
1. set d(x) = y
2. interchange the variables, so y becomes x and x becomes y
3. solve the equation for y
<u>step 1:</u> set d(x) = y
y = -2x -6
<u>step 2:</u> interchanging the variables
y = -2x - 6 turns into x = -2y - 6
<u>step 3:</u> solving for y
x = -2y - 6 < add 6 to both sides to get rid of it on the right
x + 6 = -2y < divide both sides by -2 to get y alone
x + 6 / -2 =
-2y / -2 = y
= y
so the inverse of the function is
It kinda depends on what you mean by special characters
A distributed computer system consists of multiple software components that are on multiple computers, but run as a single system. The computers that are in a distributed system can be physically close together and connected by a local network, or they can be geographically distant and connected by a wide area network.
Answer:
Following is the program in C++ Language
#include <iostream> // header file
using namespace std; // namespace std
int main() // main method
{
int n; // variable declaration
cout<<" Please enter the number :";
cin>>n; // Read the number
if(n>0) // check the condition when number is positive
{
cout<<n<<endl<<"The number is Positive"; // Display number
}
else if(n<0) // check the condition when number is Negative
{
cout<<n<<endl<<"The number is Negative";// Display number
}
else // check the condition when number is Zero
{
cout<<n<<endl<<"The number is Zero";// Display number
}
return 0;
}
Output:
Please enter the number:
64
The number is Positive
Explanation:
Following are the description of the program
- Declared a variable "n" of int type.
- Read the value of "n" by user.
- Check the condition of positive number by using if block statement .If n>0 it print the number is positive.
- Check the condition of negative number by using else if block statement If n<0 it print the number is negative.
- Finally if both the above condition is fail it print the message " The number is Zero"
