$x^2-6x-5=0\qquad\text{add 5 to both sides}\\\\x^2-6x=5\\\\x^2-2(x)(3)=5\qquad\text{add}\ 3^2\ \text{to both sides}\\\\x^2-2(x)(3)+3^2=5+3^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\(x-3)^2=5+9\\\\(x-3)^2=14\to x-3=\pm\sqrt{14}\qquad\text{add 3 to both sides}\\\\x=3-\sqrt{14}\ \vee\ x=3+\sqrt{14}$

8 0

3 years ago

-4x - 10x<br> Combine Like Terms

kondaur [170]

Answer:

-14x

Step-by-step explanation:

-4x+-10x =-14x

5 0

3 years ago

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If you place a 24-foot ladder against the top of a 22-foot building, how many feet will the bottom of the ladder be from the bot

Naddika [18.5K]

Answer:

9.6

Step-by-step explanation:

Use the Pythagorean Theorem

a² + b² = c²

Plug in the knowns

a² + 22² = 24²

Subtract 22² from both sides

a² = 24² - 22²

a² = 576 - 484

a² = 92

Take the square root of both sides

a = 9.591663046625438

Rounded

a = 9.6 ft

8 0

3 years ago

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