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GaryK [48]
3 years ago
8

Equation using the quadratic fromula for 0.05x^2 + 1.1x = 250

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
3 0

Answer:

x=60.56, x=-82.56

Step-by-step explanation:

Solve using quadratic formula

Formula is

x=\frac{-b+-\sqrt{b^2-4ac}}{2a}

0.05x^2 + 1.1x = 250

Subtract 250 on both sides

0.05x^2 + 1.1x - 250=0

a= 0.05, b=1.1 , c=-250

Plug in the values in the formula

x=\frac{-1.1+-\sqrt{(1.1)^2-4(0.05)(-250)}}{2(0.05)}

x=\frac{-1.1+-7.156116265}{0.1}

Now make two equations , one with +  and one with -

then we solve for x

x=\frac{-1.1+7.156116265}{0.1}

x=60.56

x=\frac{-1.1-7.156116265}{0.1}

x=-82.56


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