Question

Equation using the quadratic fromula for 0.05x^2 + 1.1x = 250

Answer 1

Answer:

x=60.56, x=-82.56

Step-by-step explanation:

Solve using quadratic formula

Formula is

$x=\frac{-b+-\sqrt{b^2-4ac}}{2a}$

0.05x^2 + 1.1x = 250

Subtract 250 on both sides

0.05x^2 + 1.1x - 250=0

a= 0.05, b=1.1 , c=-250

Plug in the values in the formula

$x=\frac{-1.1+-\sqrt{(1.1)^2-4(0.05)(-250)}}{2(0.05)}$

$x=\frac{-1.1+-7.156116265}{0.1}$

Now make two equations , one with +  and one with -

then we solve for x

$x=\frac{-1.1+7.156116265}{0.1}$

x=60.56

$x=\frac{-1.1-7.156116265}{0.1}$

x=-82.56