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velikii [3]
3 years ago
12

The sum of seven and the quotient of a number x and eight

Mathematics
2 answers:
salantis [7]3 years ago
6 0
7 + (x/8) in written form. I hope this helps! -Dan
KiRa [710]3 years ago
5 0
X÷8=7                 
here is how I got it...

The sum of seven soo... sum mean equals soo... something equals seven
and the quotient soo... quotient equals divide soo... what we have here right now is  x÷x=7 (x is what we dont know)
number x and eight soo... x÷8=7

       
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What is the compund interest on 5,000 over 3 years at 5% interest
Katena32 [7]

Answer:

788.13  to the nearest hundredth.

Step-by-step explanation:

Let A be the total amount in the account after 3 years.

The formula is A = P(1 + x/100)^t .

Here P = 5000, x = 5 %  and the time t = 3. years.  

Amount after 3 years = 5000(1 + 5/100)^3

=  5788.13

So the Interest is 5788.13 - 5000

= 788.13.

8 0
3 years ago
Read 2 more answers
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algol [13]
0 because 0 times anything is 0
8 0
4 years ago
Find a compact form for generating functions of the sequence 1, 8,27,... , k^3
pantera1 [17]

This sequence has generating function

F(x)=\displaystyle\sum_{k\ge0}k^3x^k

(if we include k=0 for a moment)

Recall that for |x|, we have

\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k

Take the derivative to get

\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k

\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k

Take the derivative again:

\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k

\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k

Take the derivative one more time:

\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k

\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k

so we have

\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}

5 0
3 years ago
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Anvisha [2.4K]

Answer:

A, B, E

Step-by-step explanation:

I'm not too sure about B, but A and E are definitely true

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The answer is 1/5 or 20% or .20
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