Answer: The area of the new parallelogram is multiplied by 18
Step-by-step explanation: Let the base and the height of the original parallelogram be ' x '
Base of the parallelogram = x
Height of the parallelogram = x
Area of parallelogram = l × b = lb
= x × x = x²
∴ Area of the original parallelogram = x²
∴ The base is multiplied by 3 = 3x
The height is multiplied by 6 = 6x
∴ Area of new parallelogram = 3x × 6x = 18x²
∴ The area of the new parallelogram is multiplied by = 18x²/ x²
= 18
<u><em>Please mark this as brainliest</em></u>
1 foot is 12 inches which makes 14 1.2
6.6-1.2= 5'4 george
richard is 6'0
Using the Pythagoras theorem
8^2 = 5^2 + x^2 where x = 1/2 length of the base
x^2 = 64-25 = 39
x = = sqrt39 = 6.24
so base length = 2*6.24 = 12.5 cm to nearest tenth
We know that the slope-intercept form of an equation is represented by:
y = mx + b
Where m is the slope, b is the y-intercept, and x and y pertain to points on the line in the graph.
So the slope of the line is know to be 3, and we are able to plug that into the equation:
y = 3x + b
We also know that the point (-2, 6) is on the line. With this information, we can then plug in the point into the equation to find b:
6 = 3(-2) + b
Then we can solve for b:
6 = -6 + b
b = 12
Knowing that b is 12, we can then rewrite the equation in a more general slope-intercept form that is applicable to any point on that line:
y = 3x + 12
Thus, your answer would be C.
