Question

. One car traveled 210 miles and drove 20 mph hour faster than a second car drove 150 miles. If the cars were traveling for the same time, how fast was the first car traveling?

Answer 1

Answer:

The first car was traveling 70 mph, while the second was driving 50 mph.

Step-by-step explanation:

Set the cars as a proportion:

$\frac{210}{x + 2} = \frac{150}{x}$

X represents the speed of the second car. By cross multiplying, you get the following equation:

$210x = 150(x + 20)$

You solve by distributing 150 to get 210x = 150x + 3000.

Solving for x gets you 50.

That means the first car was going at 50 mph. Adding 20, you get 70 as the speed for the second car.