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labwork [276]
3 years ago
7

7 to the fifth power divided by 7 to the fourthenth power equal 7 to the what power

Mathematics
2 answers:
Rudiy273 years ago
5 0
7⁵ : 7¹⁴ = 7⁵⁻¹⁴ = 7⁻⁹
_______________
Tresset [83]3 years ago
3 0
7^5 / 7^14

Subtract the exponents:

7^5 / 7^14 = 7^-9
You might be interested in
Help me please asap thank you
Korolek [52]

Answer:

3/5

Step-by-step explanation:

The line is going up so it is positive and it is over 3 and up 5 so it would be 3/5.

Hope this helps! Sry if i get it wrong!

3 0
2 years ago
What is the value of the expression below when z=6?<br><br> Z to the 2nd power +3z -3
aleksklad [387]
6^2= 36
3 times 6 = 18
36+18-3 =
Answer is 51
I hope this is correct :)
7 0
2 years ago
In the Volume of Cylinders, Cones and Spheres section, what is the volume of a sphere with a radius of 6in? *
Rudiy27

Answer:

The volume of the sphere is 288π in³

Step-by-step explanation:

To calculate the volume of a sphere we have to use the following formula:

V = volume

r = radius

V = ⁴⁄₃πr³

V = ⁴⁄₃ * π * (6in)³

V = π * ⁴⁄₃ * 216 in³

V = 288π in³

The volume of the sphere is 288π in³

4 0
3 years ago
The value of a car bought new for $28900 decreases 15% each year. Identify the function for the value of the car. Does the funct
Eva8 [605]

Answer:

<u>V (t) = 28,900 - 4,335t</u>

<u>The function clearly represent a decay</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Value of the car = $ 28,900

Annual depreciation = 15% = 0.15

2. Identify the function for the value of the car. Does the function represent growth or decay?

Let y represent the value of the car after t years of utilization, let p the price of the car and d, the annual depreciation, therefore:

V (t) = p - (d * t * p)

Replacing with the values we know:

V (t) = 28,900 - (0.15 * t * 28.900)

V (t) = 28,900 - (0.15 * t * 28.900)

<u>V (t) = 28,900 - 4,335t</u>

<u>The function clearly represent a decay.</u>

8 0
3 years ago
Classwork 12.1 surface area
s344n2d4d5 [400]

Answer:

6) LA = 90 units² and SA = 202 units²

7) LA = 377 units² and SA = 477.5 units²

8) LA = 208 units² and SA = 232 units²

9) LA = 455 units² and SA = 591 units²

Step-by-step explanation:

* Lets revise the rules of lateral area and surface area

- Lateral area of the solid = perimeter of its base × its height

- Surface area = lateral area + 2 × area of its base

* Now lets solve the problems

6) The solid is a rectangular prism

- Its base is a rectangle with dimensions 8 units and 7 units

- Its height is 3 units

∵ Perimeter of the rectangle = 2(L + W)

∴ Perimeter of the base = 2(8 + 7) = 2(15) = 30 units

∴ LA = 30 × 3 = 90 units²

∵ Area of the rectangle = L × W

∴ Area of the base = 8 × 7 = 56 units²

∴ SA = 90 + 2 × 56 = 90 + 112 = 202 units²

7) The solid is a cylinder

- Its base is a circle with diameter 8 units

∴ Its radius = 8 ÷ 2 = 4 units

- Its height is 15 units

∵ The perimeter of the circle is 2πr

∴ The perimeter of the base = 2π(4) = 8π

∴ LA = 8π(15) = 120π = 376.99 ≅ 377 units²

∵ The area of the circle = πr²

∴ The area of the base = π(4)² = 16π

∴ SA = 120π + 2 × 16π = 120π + 32π = 152π = 477.5 units²

6) The solid is a triangular prism

- Its base is a triangle with sides 5 , 5 , 6 units and height 4 units

- Its height is 13 units

∵ Perimeter of the triangle is the sum of the 3 sides

∴ Perimeter of the base = 5 + 5 + 6 = 16 units

∴ LA = 16 × 13 = 208 units²

∵ Area of the triangle = 1/2 × base × height

∴ Area of the base = 1/2 × 6 × 4 = 12 units²

∴ SA = 208 + 2 × 12 = 208 + 24 = 232 units²

9) The solid is a prism

- Its base is an isosceles trapezium with parallel bases 7 units and 10

 units, 2 non-parallel bases 9 units and height 8 units

- Its height is 13 units

∵ Perimeter of the trapezium is the sum of its sides

∴ Perimeter of the base = 7 + 10 + 9 + 9 = 35 units

∴ LA = 35 × 13 = 455 units²

∵ Area of the trapezium = 1/2(b1 + b2) × h

∴ Area of the base = 1/2(7 + 10) × 8 = 68 units²

∴ SA = 455 + 2 × 68 = 455 + 136 = 591 units²

6 0
3 years ago
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