It's 4 let me explain

irina [24]

Answer:

3x + 4

Step-by-step explanation:

We have a product of 3 and x. That's rewritten as 3x. We then have 4 more, so we add 4. That gives us the final answer of: 3x+4. (It is 1-4x for the third one). ( The fourth one) The sum of seven and the quotient of a number x and eight

Here, x be the number.

" quotient of a number x and eight" translated to x/8

Sum means '+'

"sum of seven and the quotient of a number x and eight" translated to 7+ x/8 +56+x/8

then; the given statement is 56+x/8

⇒

Therefore, the given statement is 56+x/8

6 0

3 years ago

Given that f(x)=x/2+5,<br> a)find f(2)<br> b)find f^-1(x)<br> c)find f^-1(5)

Aleks04 [339]

A) 6
b) x/f
c) 5/f

Mark brainliest please

Hope this helps you

8 0

2 years ago

Derivative of<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B3x%7D%5E%7B2%7D%20-%202x%20-%201%20%7D%7B%20%7Bx%7D%5E%7B2

Anastaziya [24]

Answer:

$\displaystyle \frac{dy}{dx} = \frac{2x + 2}{x^3}$

Step-by-step explanation:

we would like to figure out the derivative of the following:

$\displaystyle \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }$

to do so, let,

$\displaystyle y = \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }$

By simplifying we acquire:

$\displaystyle y = 3 - \frac{2}{x} - \frac{1}{ {x}^{2} }$

use law of exponent which yields:

$\displaystyle y = 3 - 2 {x}^{ - 1} - { {x}^{ - 2} }$

take derivative in both sides:

$\displaystyle \frac{dy}{dx} = \frac{d}{dx} (3 - 2 {x}^{ - 1} - { {x}^{ - 2} } )$

use sum derivation rule which yields:

$\rm\displaystyle \frac{dy}{dx} = \frac{d}{dx} 3 - \frac{d}{dx} 2 {x}^{ - 1} - \frac{d}{dx} {x}^{ - 2}$

By constant derivation we acquire:

$\rm\displaystyle \frac{dy}{dx} = 0 - \frac{d}{dx} 2 {x}^{ - 1} - \frac{d}{dx} {x}^{ - 2}$

use exponent rule of derivation which yields:

$\rm\displaystyle \frac{dy}{dx} = 0 - ( - 2 {x}^{ - 1 -1} ) - ( - 2 {x}^{ - 2 - 1} )$

simplify exponent:

$\rm\displaystyle \frac{dy}{dx} = 0 - ( - 2 {x}^{ -2} ) - ( - 2 {x}^{ - 3} )$

two negatives make positive so,

$\displaystyle \frac{dy}{dx} = 2 {x}^{ -2} + 2 {x}^{ - 3}$

<h3>further simplification if needed:</h3>

by law of exponent we acquire:

$\displaystyle \frac{dy}{dx} = \frac{2 }{x^2}+ \frac{2}{x^3}$

simplify addition:

$\displaystyle \frac{dy}{dx} = \frac{2x + 2}{x^3}$

and we are done!

5 0

3 years ago

Which compound inequality has no solution? x > 2 and 3x ≤ 9 x > 1 and 2x ≤ –2 x > –1 and 4x ≥ –8 x > –2 and 5x ≥ 15

antoniya [11.8K]

Answer:

4x > -8

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

a. It is important to label all your variables and expressions clearly because: it will help you get your equations set up c. it

sveticcg [70]

Answer:

I'm pretty sure it's A. It will help you get your equations set up correctly

Step-by-step explanation:

For anyone needing this answer in the future lol

3 0

2 years ago