78 * 5 i need the answer now pls.
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Answer:
We can only be certain that <em>a</em> weighs 12.
There are infinitely many possiblities for <em>b</em> and <em>c</em>.
Step-by-step explanation:
We have the equation:
Each variable indicates a weight.
We would like to determine the weights of each variable (if possible).
First, we can rearrange the equation to acquire:
We can combine like terms:
Notice that both sides have 2<em>b</em> and 3<em>c</em>. Therefore, it is possible for us to cancel them since each nullify the other side. So, we will subtract 2<em>b</em> and 3<em>c</em> from both sides. This yields:
Therefore, we can solve for <em>a</em>. Subtract 2<em>a</em> from both sides:
Hence, the weight of <em>a</em> is 12.
Using the newly acquired information, we can go back to our simplified equation:
Since <em>a</em> is 12:
Evaluate:
Simplify:
We can subtract 36 from both sides:
As you can see, this is a true statement.
Since this is a true statement, there are infinitely many possible values for <em>b</em> and <em>c</em>.
Therefore, the only weight we are <em>certain</em> of knowing is weight <em>a</em> weighing 12.
Answer:
Therefore the required Equation of Circle
Step-by-step explanation:
Given:
End point of Diameter be
point A( x₁ , y₁) ≡ ( -2 ,-2 )
point B( x₂ , y₂) ≡ ( 4 , -10 )
To Find:
Equation of a circle =?
Solution:
When end points of the Diameter are A( x₁ , y₁) , B( x₂ , y₂). then the Equation of Circle is given as
Substituting the end point are
Applying Distributive Property we get
Therefore the required Equation of Circle
Answer:
Probability of getting doubles = 1/4
Step-by-step explanation:
Given - A fair four-sided spinner has the numbers 1 to 4 marked on its sides. It is spun twice and the two scores are added together.
To find - Using a sample space diagram, find the probability of getting a double.
Proof -
Given that,
A four-sided spinner is spin twice.
So,
The Sample Space becomes
S = { (1, 1), (1, 2), (1, 3), (1, 4)
(2, 1), (2, 2), (2, 3), (2, 4)
(3, 1), (3, 2), (3, 3), (3, 4)
(4, 1), (4, 2), (4, 3), (4, 4) }
So,
n(S) = 16
Now,
Let A is the event Getting a double, So,
A = { (1, 1), (2, 2), (3, 3), (4, 4) }
and
n(A) = 4
So,
The Probability of getting doubles = n(A) ÷ n(S)
= 4 ÷ 16
= 1/4
∴ we get
Probability of getting doubles = 1/4
Answer:
Therefore values of a and b are
Step-by-step explanation:
Rewrite in the form
where a and b are integers,
To Find:
a = ?
b = ?
Solution:
..............Given
Which can be written as
Adding half coefficient of X square on both the side we get
...................( 1 )
By identity we have (A - B)² =A² - 2AB + B²
Therefore,
Substituting in equation 1 we get
Which is in the form of
On comparing we get
a = 3 and b = 2
Therefore values of a and b are