Question

Rewrite x2 − 6x + 7 = 0 in the form (x − a)2 = b, where a and b are integers, to determine the a and b values.

Answer 1

Answer:

Therefore values of a and b are

$a=3\ and\ b = 2$

Step-by-step explanation:

Rewrite $x^{2}-6x+7=0$ in the form

$(x-a)^{2}=b$

where a and b are integers,

To Find:

a = ?

b = ?

Solution:

$x^{2}-6x+7=0$ ..............Given

Which can be written as

$x^{2}-6x=-7$

$(\frac{1}{2} coefficient\ of\ x)^{2}=(\frac{1}{2}\times -6)^{2}=9$

Adding half coefficient of X square on both the side we get

$x^{2}-6x+9=-7+9=2$ ...................( 1 )

By identity we have (A - B)² =A² - 2AB + B²

Therefore,

$x^{2}-6x+9=x^{2}-2\times 3\times x+3^{2}=(x-3)^{2}$

Substituting in equation 1 we get

$(x-3)^{2}=2$

Which is in the form of

$(x-a)^{2}=b$

On comparing we get

a = 3 and b = 2

Therefore values of a and b are

$a=3\ and\ b = 2$