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dimaraw [331]
3 years ago
13

A process is turning out end items that have defects of type a, or type b, or both. if the probability of type a defect is 0.1 a

nd of type b is 0.2, the probability that an end item will have defects is:
Mathematics
1 answer:
Andreas93 [3]3 years ago
3 0
 the probability will end up being
0.28
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The mean of seven numbers is 12.0. When one new number is added , the average of eight numbers becomes 12.5 . What is the new nu
Gnesinka [82]
(12 * 7 + n)8=12.5
(12 * 7 + n)= 100
N= 16. The new number will be 16. Hope this helps. :)
8 0
3 years ago
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Pls pls pls help me i would appreciate if u help me
OlgaM077 [116]

Answer: I believe that the answer is B

Step-by-step explanation: The square root of 3 is an irrational number and 2 is a rational number thereby eliminating answer choices C and D. Thereafter, the product of the two numbers is 3.46410161514 which I believe to be an irrational number therefore eliminating A and B is your correct answer

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Could someone explain how they get the answer for this?
jarptica [38.1K]

Answer:

40°

Step-by-step explanation:

The reference angle is the positive acute angle created by the terminal arm and the x-axis.

The highlighted red in the picture below shows what we're looking for.

The arm rotated 220° (but 'backwards' so the value given is negative).

|-220°| - 2(90°)          <= Subtract two right angles for two quadrants

= 220° - 2(90°)

= 220° - 180°

= 40°

Therefore, the reference angle is 40°.

If you got 50°, you probably calculated the angle with the terminal arm and the y-axis. Remember to always use the nearest side of the x-axis!

4 0
3 years ago
The previous balance of Sam's saving account was $1345.67. He makes thevfollowing transactions: deposits, $228.48, $74.36; withd
mylen [45]

Answer:

Step-by-step explanation:

2192

3 0
3 years ago
If f(x)=x-1/3 and g(x)=3x+1, what is (f o g)(x)?
BlackZzzverrR [31]

Answer:

\[3x+\frac{2}{3}\]

Step-by-step explanation:

\[f(x)=x-\frac{1}{3}\]

\[g(x)=3x+1\]

Hence, \[(f o g)(x)=f(3x+1)\]

But, \[f(3x+1)=(3x+1)-\frac{1}{3}\]

Simplifying,

\[f(3x+1)=3x+(1-\frac{1}{3})\]

= \[f(3x+1)=3x+(\frac{3-1}{3})\]

= \[f(3x+1)=3x+(\frac{2}{3})\]

Hence, \[(f o g)(x)=3x+(\frac{2}{3})\]

8 0
3 years ago
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