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Marat540 [252]
3 years ago
10

Which of the following is an algebraic expression that represents the phrase X increased by 20

Mathematics
1 answer:
iren2701 [21]3 years ago
5 0

Answer:

The expression means that X+20

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28 ft per min = 0.512064 km per hour
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Which fraction is equivalent to 38%?<br> 3/8<br> 9/25<br> 19/50<br> 3 4\5
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In order to find a fraction, We know that a percentage is out of a 100. This means we can now place our fraction as:

38/100

In order to find the actual fraction, we will want to simplify. Lets find our least common factor and work down from there. Since we know that 2 can go into both of them, lets reduce by 2.

This means our fraction will now look like: 

19/50

Since 19 is a prime number and cannot be divided by anything but 1 and itself, we know that this is our simplified form. 

This means:

19/50 is the fraction equivalent to 38%. 
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if you are 15 years old now, which equation could be used to solve for your age, y, 12 years from now ?
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Hi there!

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Which of the following is the conjugate of a complex number with 4 as the real part and −3i as the imaginary part?
White raven [17]

Answer:

4+3i

Step-by-step explanation:

we know that

To find the conjugate complex of a complex number, simply change the sign of the imaginary part of the complex number

In this problem we have

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Can someone help me with this​
SashulF [63]

Answer:

\angle NRQ =85 \degree

Given:

\angle RPQ = 45 \degree \\  \angle PQR = (6x + 4)\degree \\  \angle NRQ = (15x - 5)\degree

Step-by-step explanation:

Property used: <em>An exterior angle of a triangle is equal to the sum of the opposite int</em><em>e</em><em>rior angles.</em>

<em>=  >  \angle RPQ +  \angle PQR =  \angle NRQ \\  \\  =  > 45 \degree + (6x + 4)\degree = (15x - 5)\degree \\  \\  =  > 45\degree + 6x\degree + 4\degree = 15x\degree - 5\degree \\  \\  =  > 49\degree  + 5 \degree= 15x\degree - 6x\degree \\  \\  =  > 54\degree = 9x\degree \\  \\  =  > 9x\degree = 54\degree \\  \\  =  > x\degree =  (\frac{54}{9} )\degree \\  \\  =  > x\degree = 6\degree \\  \\ Putting \: value \: of \: x \: in \:  \angle NRQ  \\   \\  =  > \angle NRQ = (15x - 5)\degree \\  \\  =  >  \angle NRQ = (15 \times 6 - 5) \degree \\  \\  =  >  \angle NRQ =85 \degree</em>

4 0
3 years ago
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