Question

Brahmagupta’s solution to a quadratic equation of the form ax2 + bx = c involved only one solution. Which solution would he have found for the equation 3x2 + 4x = 6?

Answer 1

Answer:

$\text{The solution is }\frac{\sqrt{88}-4}{6}$

Step-by-step explanation:

Given that Brahmagupta’s solution to a quadratic equation of the form

$ax^2+bx=c$ involved only one solution.

we have to find the solution for the equation

$3x^2 + 4x = 6$

$\text{The solution for the equation }ax^2+bx=c$ is

$x=\frac{\sqrt{4ac+b^2}-b}{2a}$

$\text{The solution for the equation }3x^2+4x=6$ is

$x=\frac{\sqrt{4(3)(6)+4^2}-4}{2(3)}$

$x=\frac{\sqrt{72+16}-4}{6}$

$x=\frac{\sqrt{88}-4}{6}$

Answer 2

Answer:

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