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zmey [24]
3 years ago
5

Brahmagupta’s solution to a quadratic equation of the form ax2 + bx = c involved only one solution. Which solution would he have

found for the equation 3x2 + 4x = 6?
Mathematics
2 answers:
sineoko [7]3 years ago
7 0

Answer:

\text{The solution is }\frac{\sqrt{88}-4}{6}

Step-by-step explanation:

Given that Brahmagupta’s solution to a quadratic equation of the form

ax^2+bx=c involved only one solution.

we have to find the solution for the equation

3x^2 + 4x = 6

\text{The solution for the equation }ax^2+bx=c is

x=\frac{\sqrt{4ac+b^2}-b}{2a}

\text{The solution for the equation }3x^2+4x=6 is

x=\frac{\sqrt{4(3)(6)+4^2}-4}{2(3)}

x=\frac{\sqrt{72+16}-4}{6}

x=\frac{\sqrt{88}-4}{6}

algol [13]3 years ago
5 0

Answer:

It's A on Edu, I just took the test and got 100

hope this helps you!

(ps.please mark me as barinlyest)

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How would you use the Fundamental Theorem of Calculus to determine the value(s) of b if the area under the graph g(x)=4x between
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The Fundamental Theorem of Calculus regarding geometry states that 
\int\limits^b_a g{(x)} \, dx = F(b)-F(a)

Where F is the indefinite integral of g(x)

The first step is to integrate g(x)
\int\ {4x} \, dx = \frac{4x^{1+1} }{1+1} = \frac{4x^{2} }{2} =2 x^{2}

Then substitute the value of b and a=1 into 2x^{2}

[2 (b)^{2}]-[2 (1)^{2}] = 240
2b^{2} -2=240
2b^{2}=240+2
2b^{2}=242
b^{2}= \frac{242}{2}
b^{2}=121
b=11

Hence the limit of the area under g(x) is between a=1 and b=11

6 0
3 years ago
If HK = 4p - 51 and JK = p, find the value of p in parallelogram GHIJ,<br> help !
MA_775_DIABLO [31]

Answer: Question not very clear

Step-by-step explanation:

I will like to see the original question, then I will attempt to help you. Surely.

5 0
3 years ago
If 6 is added to three quarters of a certain number, the result is 42 . Find the original number​
Basile [38]

Answer:

Step-by-step explanation

Hello!

3x/4 + 6=42

3x/4=42-6 = 36

3x = 36*4

3x = 144

x= 144/3 =48

3/4 of  48  = (48*3)  / 4 =36

36+6=42

the original number​ is 48

4 0
3 years ago
Read 2 more answers
Which of these is an exponential parent function?  A. f(x) = 2^x – 3  B. f(x) = 2^x + 2  C. f(x) = 2^x  D. f(x) = 2^x + 1/3
anygoal [31]

An exponential parent function is the option C. f(x)= 2^{x}, from the given options.

What do you mean by exponential parent function?

The formula for their parent function is y = b^{x}, where b is any non zero constant. Below is a graph of the parent function, y = e^{x}, which demonstrates that it will never equal 0. And at y = 1 when x = 0, y crosses the y-axis.

According to options in the given question,

We have the option below in the given question:

A. f(x) = 2^x – 3 

B. f(x) = 2^x + 2 

C. f(x) = 2^x 

D. f(x) = 2^x + 1/3

We know from the above definition that the option C. is the right answer to the given question.

Therefore, the exponential parent function is f(x)= 2^{x}.

To learn more about exponential parent function, visit:

brainly.com/question/24210615?referrer=searchResults

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4 0
1 year ago
9x (-2y + 5x) - 4 xy (6x-3y) please the person who answers will be marked as brainliest​. please show working​
Alenkasestr [34]

Answer:

See explanation

Step-by-step explanation:

9x(-2y+5x)-4xy(6x-3y)

By the distributive property this is equal to:

9x(-2y)+9x(5x)-4xy(6x)-4xy(-3y)=\\\\-18xy+45x^2-24x^2y+12xy^2

Hope this helps!

4 0
3 years ago
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