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SOVA2 [1]
3 years ago
7

Please Simplify √5 4/9​

Mathematics
1 answer:
s2008m [1.1K]3 years ago
6 0

Answer:

\frac{4\sqrt{5} }{9}

Step-by-step explanation:

Simplify the radical expression.

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Find the volume of a cylinder with a radius of 3 meters and a height of 13 meters. Use 3.14 The volume of the cylinder is Type a
zvonat [6]
<h2><u>Question</u>:-</h2>

Find the volume of a cylinder with a radius of 3 meters and a height of 13 meters.

<h2><u>Answer</u>:-</h2>

<h3>Given:-</h3>

\bullet Radius (r) of a cylinder = 3 meters.

\bullet Height (h) of a cylinder = 13 meters.

<h3>To Find:-</h3>

The volume of a cylinder.

<h2>Solution:-</h2>

We know,

Formula of Volume of a cylinder is πr²h.

So, Volume of a cylinder = 3.14 × (3)² × 13

Volume of a cylinder = 3.14 × 3 × 3 × 13

Volume of a cylinder = 367.38 cubic meters.

<h3>The volume of a cylinder is <u>3</u><u>6</u><u>7</u><u>.</u><u>3</u><u>8</u><u> </u><u>cubic </u><u>meters</u>. [Answer]</h3>
4 0
3 years ago
What’s the first step in multiplying a monomial by any polynomial
suter [353]

Answer:

distribute the monomial into the polynomial and be careful of sign errors

Step-by-step explanation:

6 0
4 years ago
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The sum of three numbers is 84 the second number is 3 times the third . The first number is 6 less then the third . What are the
Kamila [148]

Answer:

A=12

B=54

C=18

Step-by-step explanation:

A=first

B=second

C=third

A+B+C=84

B=3C

A=C-6

C-6+3C+C=84

5C-6=84

5C=90

C=18

A=C-6

=(18)-6

=12

B=3C

=3(18)

=54

7 0
4 years ago
In which quadrant of the coordinate graph does point J lie?
mihalych1998 [28]

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thats quadrant 2

Step-by-step explanation:

8 0
3 years ago
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#24, i am getting <img src="https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%260%26%5Cfrac%7B18%7D%7B7%7D%20
sveticcg [70]

It looks like you're talking about row-reducing an augmented matrix to solve the system of equations. Your answer is almost correct. The last row should read 0, 0, 1, 2/7.

The given system translates to

\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 1 & -1 & 2 & 2 \\ 1 & 2 & -3 & 4 \end{array} \right]

Eliminate x from the last two rows by combining -2 (row 2) and row 1, and -2 (row 3) and row 1; that is,

(2x - 3y + z) - 2 (x - y + 2z) = 2 - 2 (2)

2x - 3y + z - 2x + 2y - 4z = 2 - 4

-y - 3z = -2

and

(2x - 3y + z) - 2 (x + 2y - 3z) = 2 - 2 (4)

2x - 3y + z - 2x - 4y + 6z = 2 - 8

-7y + 7z = -6

In augmented matrix form, this step yields

\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & -1 & -3 & -2 \\ 0 & -7 & 7 & -6 \end{array} \right]

I'll omit these details in the remaining steps.

Eliminate y from the last row by combining -7 (row 2) and row 3 :

\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & -1 & -3 & -2 \\ 0 & 0 & 28 & 8 \end{array} \right]

Multiply the last row by 1/28 :

\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & -1 & -3 & -2 \\ 0 & 0 & 1 & 2/7 \end{array} \right]

Eliminate z from the second row by combining 3 (row 3) and row 2 :

\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & -1 & 0 & -8/7 \\ 0 & 0 & 1 & 2/7 \end{array} \right]

Multiply the second row by -1 :

\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & 1 & 0 & 8/7 \\ 0 & 0 & 1 & 2/7 \end{array} \right]

Eliminate y and z from the first row by combining 3 (row 2), -1 (row 3), and row 1 :

\left[ \begin{array}{ccc|c} 2 & 0 & 0 & 36/7 \\ 0 & 1 & 0 & 8/7 \\ 0 & 0 & 1 & 2/7 \end{array} \right]

Multiply the first row by 1/2 :

\left[ \begin{array}{ccc|c} 1 & 0 & 0 & 18/7 \\ 0 & 1 & 0 & 8/7 \\ 0 & 0 & 1 & 2/7 \end{array} \right]

8 0
3 years ago
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