All categories

3 years ago

Please help with geometry! i will give brainlist!

Mathematics

1 answer:

denis23 [38]3 years ago

6 0

Answer:

Step-by-step explanation:

$m\angle T+m\angle P=180^o\\\\(12x-4)^o+(7x+13)^o=180^o\\\\12^o\cdot x-4^o+7^o\cdot x+13^o=180^o\\\\(12^o+7^o)\cdot x=180^o+4^o-13^o\\\\19^o\cdot x=171^o\\\\x=9$

$MO=\dfrac{TR+AP}2\\\\\\16y+1=\dfrac{12y+1+18y+6}2\\\\(16y+1)\cdot2=30y+7\\\\32y+2-30y=7\\\\2y=7-2\\\\2y-5\\\\y=2.5$

You might be interested in

Express 0.0057 in scientific notation

andrew-mc [135]

Answer:

$5.7 \times {10}^{ - 3}$

Step-by-step explanation:

0.0057

first number

then the rest

equal

5.7

There's <u>three</u> zeros <u>behind</u> the number 5 which mean it will be -3

$\times {10}^{ - 3}$

final answer

$5.7 \times {10}^{ - 3}$

another example and it will be clear

0.0000403

first number

then the rest

equal

4.03

There's <u>five</u> zeros <u>behind</u> the number 4 which mean it will be -5

$\times {10}^{ - 5}$

final answer

$4.03 \times {10}^{ - 5}$

3 0

3 years ago

HELP ASAP WILL MARK BRAINLIEST AREA OF FIGURES

Lerok [7]

Answer:

1. 170.083 in³

2. 126π in³

3. 92.106 m³

4. 2412.74 in³

5. 612π m³ and 1922 m³

Step-by-step explanation:

Cylinder:

$V = \pi r^{2}h$ *Plug in numbers*

$(3.14)(2.5)^{2}(7)$ *Square 2.5*

$(3.14)(6.25)(7)$ *Solve*

≈ $137.375in^{3}$

Sphere:

$V = \frac{4}{3}\pi r^{3}$ *Plug in numbers*

$\frac{4}{3} (3.14)(2.5)^{3}$ *Cube 2.5*

$\frac{\frac{4}{3}(3.14)(15.625)}{2}$ *Divide by 2 and Solve*

≈ $32.7083 in^{3}$

Add both volumes

$137.375 + 32.7083$ ≈ $170.083in^{3}$

Cylinder:

$V = \pi r^{2}h$ *Plug in numbers*

$\pi (3)^{2}(10)$ *Square 3*

$\pi (9)(10)$ *Multiply*

$90\pi$

Sphere:

$V = \frac{4}{3}$ π $r^{3}$ *Plug in numbers*

$\frac{4}{3}\pi (3)^{3}$ *Cube 3*

$\frac{4}{3} \pi (27)$ *Multiply*

$36\pi$

Add both Volumes to get total

$90\pi + 36\pi = 126in^{3}$

Sphere:

$V = \frac{4}{3}\pi r^{3}$ *Plug in numbers*

$\frac{4}{3} (3.14)(3)^{3}$ *Cube 3*

$\frac{4}{3} (3.14)(27)$ *Multiply*

$113.04m^{3}$

Cone:

$V = \frac{\pi r^{2}h}{3}$ *Plug in numbers*

$\frac{(3.14)(2)^{2}(5)}{3}$ *Square 2*

$\frac{(3.14)(4)(5)}{3}$ *Solve*

$20.93m^{3}$

Subtract the volumes to get the volume of the blue area

$113.04 - 20.93 = 92.106m^{3}$

Sphere:

$V = \frac{4}{3} \pi r^{3}$ *Plug in numbers*

$\frac{4}{3}\pi (8)^{3}$ *Cube 8*

$\\\frac{4}{3}\pi (512)$ *Multiply*

$\\\\\pi (682.6)$ *Solve*

$2133.66in^{3}$ *Divide by 2 since it's a hemisphere*

Cone:

$V = \frac{\pi r^{2}h}{3}$ *Plug in numbers*

$\frac{\pi (8)^{2}(20)}{3}$ *Square 8*

$\frac{\pi (64)(20)}{3}$ *Multiply and Divide*

$1340.41 in^{3}$

Add both volumes

$1072.33 + 1340.41 = 2412.74in^{3}$

Cylinder:

$V = \pi r^{2}h$ *Plug in numbers*

$\pi (6)^{2}(16)$ *Square 6*

$\pi (36)(16)$ *Multiply*

$576\pi$

Cone:

$V = \frac{\pi r^{2}h}{3}$ *Plug in numbers*

$\frac{\pi (6)^{2}3}{3}$ *Square 6*

$36\pi$

Add both volumes

$576\pi + 36\pi = 612\pi m^{3}$

Alternative: *Multiply π*

$1922m^{3}$

4 0

3 years ago

Read 2 more answers

Evaluate 8j -k+14 when j = 0.25 and k =1

Amiraneli [1.4K]

Substitute
8(0.25) -1+14 = 15

7 0

3 years ago

Read 2 more answers

The lengths of two sides of a right triangle are 12 inches and 15 inches. What is the difference between the two possible length

ipn [44]

The problem is using a right triangle, it means we can use the Pythagorean theorem in solving the problem. We have two possible measurements for the third side.
First length, when the third side is the hypotenuse:
x ² = 15² + 12²
x = 19.21

Second possible length, when the third leg is either an adjacent or base side:
15² = x² + 12²
x = 9

Therefore, the difference between the two possible answers are shown below:
Difference = 19.21 - 9 = 10.21

5 0

3 years ago

Can anyone help plz thanks if u help

s344n2d4d5 [400]

Answer:

68.04 cm^3

Step-by-step explanation:

The volume of the prism is given by

V = Bh

where B is the area of the base and h is the height

B - area of the triangle

B = 1/2 bh = 1/2 (5.4) (3.6) = 9.72

The volume is

V = 9.72*7

68.04 cm^3

5 0

3 years ago