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3 years ago

What is the equation of the inverse y = x^2 + 4?

Mathematics

1 answer:

Tasya [4]3 years ago

4 0

The correct answer is b

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Multiply eight and eighty-eight hundredths by two and three tenths

zimovet [89]

Answer:

20.424

Step-by-step explanation:

Given words can be written as

Eight and eighty-eight hundredths = (8+ $\frac{88}{100}$ )

= $\frac{800+88}{100}$

= 8.88

Two and three tenth = (2+ $\frac{3}{10}$ )

= $\frac{20+3}{10}$

= 2.3

Now multiply them

i.e 8.88 × 2.3 = 20.424

So 20.424 is the Answer

7 0

3 years ago

What describes a triangle if given segments are 3, 5 and 3

forsale [732]

Answer:

An obtuse triangle?

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

The height of a parallelogram is three times its base. If the area is 972 square inches, what is the base and height?

Fed [463]

So h is 3x
b is x
3x plus x equal 972
4x = 972
243 is base
243 times 3 is 729

8 0

3 years ago

Help me please 10 pts for you mark you brainliest

Lena [83]

Answer 1: A and C

Step-by-step explanation:

Use distribution law to see which answer match the equation at the top.

Answer 2: 16q + 4

10q and 6q are like terms

10q + 6q = 16q

5 - 1

8 0

2 years ago

Read 2 more answers

Cubed root x cubed root x2

Yuki888 [10]

Answer:

Final answer is $\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x$ .

Step-by-step explanation:

Given problem is $\sqrt[3]{x}\cdot\sqrt[3]{x^2}$ .

Now we need to simplify this problem.

$\sqrt[3]{x}\cdot\sqrt[3]{x^2}$

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}$

Apply formula

$\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}$

so we get:

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}$

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}$

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x$

Hence final answer is $\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x$ .

7 0

3 years ago