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kirza4 [7]
3 years ago
15

The distance from Palo Alto, CA and Columbus, OH is 2,470 miles. Due to the winds it takes 4 hours and 20 minutes to fly to Ohio

, but 5 hours on the return trip (which is the same distance). Find the ground speed of the plane assuming that plane ground speed and wind speed remain constant.
Mathematics
1 answer:
frutty [35]3 years ago
4 0

Answer: 494 mph

Step-by-step explanation:

S=d/t

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There are only 5 blue cards, 2 green cards and 4 red cards in a pack.
Ainat [17]

Answer:

5/11 or 45 percent, since there are 5 blue cards

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Help T-T I’m a bit stuck
ddd [48]

Answer:

It is the 3rd option. If it doesn't have a line below it, the circle should be open. And where the arrow points is where your line should go if that makes sense.

Step-by-step explanation:

4 0
3 years ago
0.7 (3s + 4)-1.1s = 7.9
vichka [17]

Answer:

s = 5.1

Step-by-step explanation:

0.7 (3s + 4)-1.1s = 7.9\\

Multiply both sides of the equation by 10

0.7\left(3s+4\right)\cdot \:10-1.1s\cdot \:10=7.9\cdot \:10\\\\= 7\left(3s+4\right)-11s=79\\

Expand

\mathrm{Expand\:}7\left(3s+4\right)-11s:\\\quad 10s+28

Subtract 28 from both sides

10s+28-28=79-28

Simplify

10s=51

Divide both sides of the equation by 10

\frac{10s}{10}=\frac{51}{10}

Simplify

s=\frac{51}{10}\\\\Decimal = 5.1

3 0
3 years ago
Read 2 more answers
A 50 gallon water tank is to be used for irrigating a garden. If it is full, and water is used from it at a constant rate of 2 g
mihalych1998 [28]

25. 50/2=25 here is you answer.

6 0
3 years ago
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A plan for a park has a rectangular plot of wild flowers that needs to be enclosed by 54 feet of fencing. Only three sides need
Gekata [30.6K]

SOLUTION:

Step 1:

In this question, we are given the following:

Step 2:

a) What is the largest area possible for the garden?

Now, let the length of the rectangular plot be 54 -2x,

and the width of the rectangular plot be x,

so that:

\begin{gathered} \text{Area = (54 -2x) x = 54 x -2x}^2 \\ \frac{dA}{dx}=\text{ 54 - 4x = 0} \\ We\text{ have that:} \\ 54\text{ = 4x } \\ \text{Divide both sides by 4, we have that:} \\ \text{x = }\frac{54}{4} \\ \text{x = 13. 5} \end{gathered}

Then, the largest area possible for the garden will be:

\text{Area = 54x -2x}^2=54(13.5)-2(13.5)^2=729-364.5=364.5ft^2

b) What width will produce the maximum area?

Width,\text{ x = 13. 5 fe}et

c) The length of the garden that will produce the maximum area:

\text{Length = 54 - 2x = 54 - 2( 13. 5) = 54 -27 = 27 fe}et

5 0
1 year ago
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