first you start with y=mx+b find the y intercept first which is 1 next you just count down the block which is 3 then count to the right till you find a spot where it lands which would get you y=3/4+1

5 0

2 years ago

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A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 ce

julsineya [31]

Answer:

The proportion of students whose height are lower than Darnell's height is 71.57%

Step-by-step explanation:

The complete question is:

A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 centimeters. Darnel is a middle school student with a height of 161.4cm.

What proportion of proportion of students height are lower than Darnell's height.

Answer:

We first calculate the z-score corresponding to Darnell's height using:

$Z=\frac{X-\mu}{\sigma}$

We substitute x=161.4 , $\mu=150$ , and $\sigma=20$ to get:

$Z=\frac{161.4-150}{20} \\Z=0.57$

From the normal distribution table, we read 0.5 under 7.

The corresponding area is 0.7157

Therefore the proportion of students whose height are lower than Darnell's height is 71.57%

8 0

2 years ago

Help I have a lot to do

BaLLatris [955]

12)
(intro) Slope is change in y divided by change in x (axes). Here, the y axis is depth and the x axis is hours. So, the slope is change in depth between any two points, divided by the change in hours between the same points. The slope of this line is half a foot depth divided by 2 hours.
a) So, the slope is 0.5 / 2 = 0.25, or 1/4.
b) The graph shows a constant rate of change because the line is straight (it increases at the same speed. If the line was curving, it would not be a constant rate of change).
c) Yes, because the line has a constant rate of change now.

4 0

2 years ago