Answer:
Idkasd
Step-by-step explanation:
Keep trying
complete question:
The sum of the digits of a two-digit numeral is 8. If the digits are reversed, the new number is 18 greater than the original number. How do you find the original numeral?
Answer:
The original number is 10a + b = 10 × 3 + 5 = 35
Step-by-step explanation:
Let
the number = ab
a occupies the tens place while b occupies the unit place. Therefore,
10a + b
The sum of the digits of two-digits numeral
a + b = 8..........(i)
If the digits are reversed. The reverse digit will be 10b + a. The new number is 18 greater than the original number.
Therefore,
10b + a = 18 + 10a + b
10b - b + a - 10a = 18
9b - 9a = 18
divide both sides by 9
b - a = 2...............(ii)
a + b = 8..........(i)
b - a = 2...............(ii)
b = 2 + a from equation (ii)
Insert the value of b in equation (i)
a + (2 + a) = 8
2a + 2 = 8
2a = 6
a = 6/2
a = 3
Insert the value of a in equation(ii)
b - 3 = 2
b = 2 + 3
b = 5
The original number is 10a + b = 10 × 3 + 5 = 35
Answer:
Step-by-step explanation:
Let
Y ----> field of vision that Yash's camera would need
we know that
Applying the law of sines
Solve for sin(Y)
![Y=sin^{-1}[\frac{sin(41\°)}{30}(25)]](https://tex.z-dn.net/?f=Y%3Dsin%5E%7B-1%7D%5B%5Cfrac%7Bsin%2841%5C%C2%B0%29%7D%7B30%7D%2825%29%5D)
Answer:
OHHHHHHHH wait It went up by 8%!
Step-by-step explanation:
Answer:
28.740,
Step-by-step explanation:
