instead of P+2x = y it should be P-2x=y
so then it is P-2x/2 =y
Answer:
Graph 1
Domain = -8 =< x =< 10
Range = -9 =< f(x) =< 9
Graph 2
Domain = -1 =< x =< 5
Range = -1 =< f(x) =< 2
Explaination:
Domain means the inputed x values on the x-axis, so to make things simpler and to not write every individual x values. We write it with <, >, and =<. (you can see it as the 'width' of a graph).
Range means the output y values on the y-axis. It's like the 'height' of a graph. And also, to make things simpler and to not write every individual y values. We write it with <, >, and =< with f(x) too because f(x) = y.
Answer:
Step-by-step explanation:
I'm assuming you meant to type in
because you can only have removable discontinuities where there is a rational (fraction) function. Begin by factoring both the numerator and denominator to
and cancelling out like terms would have us eliminating the (x + 3). That is where there is a removable discontinuity. It leaves a hole. The other discontinuity, (x + 1) doesn't cancel out so it is a non-removable discontuinity, which is a vertical asymptote.
The removable discontinuity is at -3. There is no y value at x = -3 (remember there's only a hole here), because -3 causes the denominator to go to 0 and we all know that having a 0 in the denominator of a fraction is a big no-no!!!
Answer:
7. 7.8
Step-by-step explanation:
We can use Tan of this angle to find the missing side (in this case, the side adjacent to the angle measuring 57°)
Tan A = (opposite side)/(adjacent side)
Tan 57° = 12/x
solve for x
x(Tan 57°) = 12
x = 12/(Tan 57°)
x = 7.8 (rounded to the nearest tenth)
Answer:
24 inches
Step-by-step explanation:
When dealing with 3-Dimensional objects such as a box, the depth of that object refers to the distance between the highest and lowest points of that object. Therefore since it the question it states that the length, width and depth is 24 inches. Then the height of the box (as well as maximum height) would be a total of 24 inches. This would be in the case that the entire box was cubed, if the box is triangular with a square base then this height would be shorter as all the points would meet in a shorter position.
