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Ilia_Sergeevich [38]
3 years ago
5

Solve attachment 30 points!!!!!

Mathematics
1 answer:
Effectus [21]3 years ago
4 0

Answer:

A=\frac{B^3}{5g+m}

Step-by-step explanation:

Step 1: Write out equation

5gA + mA = B³

Step 2: Factor out A

A(5g + m) = B³

Step 3: Divide both sides by 5g + m

A=\frac{B^3}{5g+m}

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Nicole is running for school president. Her best friend designed a campaign poster, which measured 3 feet by 2 feet. Nicole like
melamori03 [73]

Answer:

The scale factor is 18 to 1 for the painting

Step-by-step explanation:

Here we want to get the scale factor of the original to what is reproduced

Let us have same units first

Mathematically;

1 foot = 12 inches

3 feet = 36 inches

2 feet = 24 inches

So 36 to 2 and 24 to 1 1/3

That will be ratio 36/2 = 18 to 1

same as 25 divided by 1 1/3 = 18 to 1

8 0
3 years ago
The calibration of a scale is to be checked by weighing a 13 kg test specimen 25 times. Suppose that the results of different we
Natali5045456 [20]

Solution :

a).

Given : Number of times, n = 25

            Sigma, σ = 0.200 kg

            Weight, μ = 13 kg

Therefore the hypothesis should be tested are :

$H_0 : \mu = 13 $

$H_a : \mu \neq 13$

b). When the value of $\overline x = 12.84$

 Test statics :

   $Z=\frac{(\overline x - \mu)}{\frac{\sigma}{\sqrt n}} $

  $Z=\frac{(14.82-13)}{\frac{0.2}{\sqrt {25}}} $

          $=\frac{1.82}{0.04}$

          = 45.5  

P-value = 2 x P(Z > 45.5)

            = 2 x 1 -P (Z < 45.5) = 0

Reject the null hypothesis if P value  < α = 0.01 level of significance.

So reject the null hypothesis.

Therefore, we conclude that the true mean measured weight differs from 13 kg.

3 0
3 years ago
What is 5C3?<br> A. 35<br> B. 10<br> C. 14<br> D. 28
galben [10]

Answer: B. 10

-5C3 or 5 choose 3 refers to how many combinations are possible from 5 items, taken 3 at a time. To calculate combinations, we will use the formula nCr = n! / r! ... * (n - r)!, where n represents the total number of items, and r represents the number of items being chosen at a time.

-10 is the total number of all possible combinations for choosing 3 elements at a time from 5 distinct elements without considering the order of elements in statistics & probability surveys or experiments. The number of combinations for sample space 5 CHOOSE 3 can also be written as 5C3 in the format of nCr or nCk.

Step-by-step explanation: Hope this help :D

5 0
3 years ago
Read 2 more answers
Can someone please help me
babymother [125]

Answer:

Its a i just took the test

Step-by-step explanation:

4 0
3 years ago
Math question below down below
Elanso [62]
The letter A represents the smallest value in the data collection, which would be 17
5 0
3 years ago
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