Evaluate the expressions when x = 10 & y =8.<br><br> 2y

Simplify fully square root of 8 x square root of 18

Sati [7]

Answer:

12

Step-by-step explanation:

square root of 8 = 2.82842712475

square root of 18 = 4.24264068712

4.24264068712 × 2.82842712475 = 12

4 0

3 years ago

Read 2 more answers

Classify the triangle with the given side lengths as 1,13,13

Anuta_ua [19.1K]

Answer:

isosceles triangle

Step-by-step explanation:

6 0

3 years ago

Megan drove from her house to work at an average speed of 45 miles per hour. The drive took her

Dominik [7]

Answer:

30 mph

Step-by-step explanation:

The average speed = Total distance / Total Time

Distance at 45 m/hr.

t = 20 minutes = 20/60 = 1/3 hour.

r = rate = 45 miles / hour

d = r * t

d = 45 * 1/3 = 15 miles.

Average Speed going home.

t = 30 minutes

t = 30 min / 60 min // hour = 1/2 hours

r = 15 miles / 1/2 = 15 * 2 = 30 miles / hr.

8 0

3 years ago

Alec paid the bill for dinner with his clients which totaled $140 before tax and tip. If an 8 percent sales tax was added to the

ch4aika [34]

The total cost of the dinner is $176.20.

<h3>What is the total cost of the dinner?</h3>

The total cost of the dinner is the sum of the bill for the dinner, the tax and the tip.

Total cost = tip + bill of the dinner + tip

Tax = 0.08 x 140 = $11.20

Total cost = $140 + $25 + $11.20 = $176.20

To learn more about taxes, please check: brainly.com/question/25311567

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8 0

2 years ago

The prior probabilities for events A1 and A2 are P(A1) = 0.20 and P(A2) = 0.80. It is also known that P(A1 ∩ A2) = 0. Suppose P(

Umnica [9.8K]

Answer:

(a) $A_1$ and $A_2$ are indeed mutually-exclusive.

(b) $\displaystyle P(A_1\; \cap \; B) = \frac{1}{20}$ , whereas $\displaystyle P(A_2\; \cap \; B) = \frac{1}{25}$ .

(c) $\displaystyle P(B) = \frac{9}{100}$ .

(d) $\displaystyle P(A_1 \; |\; B) \approx \frac{5}{9}$ , whereas $P(A_1 \; |\; B) = \displaystyle \frac{4}{9}$

Step-by-step explanation:

$P(A_1 \; \cap \; A_2) = 0$ means that it is impossible for events $A_1$ and $A_2$ to happen at the same time. Therefore, event $A_1$ and $A_2$ are mutually-exclusive.

By the definition of conditional probability:

$\displaystyle P(B \; | \; A_1) = \frac{P(B \; \cap \; A_1)}{P(B)} = \frac{P(A_1 \; \cap \; B)}{P(B)}$ .

Rearrange to obtain:

$\displaystyle P(A_1 \; \cap \; B) = P(B \; |\; A_1) \cdot P(A_1) = 0.25 \times 0.20 = \frac{1}{20}$ .

Similarly:

$\displaystyle P(A_2 \; \cap \; B) = P(B \; |\; A_2) \cdot P(A_2) = 0.80 \times 0.05 = \frac{1}{25}$ .

Note that:

$\begin{aligned}P(A_1 \; \cup \; A_2) &= P(A_1) + P(A_2) - P(A_1 \; \cap \; A_2) = 0.20 + 0.80 = 1\end{aligned}$ .

In other words, $A_1$ and $A_2$ are collectively-exhaustive. Since $A_1$ and $A_2$ are collectively-exhaustive and mutually-exclusive at the same time:

$\displaystyle P(B) = P(B \; \cap \; A_1) + P(B \; \cap \; A_2) = \frac{1}{20} + \frac{1}{25} = \frac{9}{100}$ .

By Bayes' Theorem:

$\begin{aligned} P(A_1 \; |\; B) &= \frac{P(B \; | \; A_1) \cdot P(A_1)}{P(B)} \\ &= \frac{0.25 \times 0.20}{9/100} = \frac{0.05 \times 100}{9} = \frac{5}{9}\end{aligned}$ .

Similarly:

$\begin{aligned} P(A_2 \; |\; B) &= \frac{P(B \; | \; A_2) \cdot P(A_2)}{P(B)} \\ &= \frac{0.05 \times 0.80}{9/100} = \frac{0.04 \times 100}{9} = \frac{4}{9}\end{aligned}$ .

6 0

3 years ago

Evaluate the expressions when x = 10 & y =8. 2y