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Rzqust [24]
3 years ago
8

Evaluate the expressions when x = 10 & y =8. 2y

Mathematics
1 answer:
klasskru [66]3 years ago
5 0

Answer: 64

Step-by-step explanation:

y=8

plug in 8 for y

2(8)=64

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Help:
dalvyx [7]

Answer:

Step-by-step explanation:

a. (11x) + (22x)= 33x

b. (-6x) - (-6x) = 0

c. (-13) + (14x) - (+13t) = -13t + 14x - 13

d. (-4t) + (+4t) - (-6t) = 6t

4 0
3 years ago
Read 2 more answers
Help me I’m dumb and stupid :)
wel

Answer:

The first digit of the quotient should be placed at the leftmost place of the places of the all the digits in the quotient.This is so from the basic rule of division.

Step-by-step explanation:

The quotient is given by,

[\frac {4,839}{15}] [where [x] is the greatest integer function on x]

= [322.6]

= 322

and the remainder is given by,

15 \times 0.6

= 9

So, the first digit of the quotient should be placed at the leftmost place of the places of the all the digits in the quotient and this is so from the very basic rule of division.

8 0
3 years ago
Help find the area, please.
Tanzania [10]
The answer is 72 !! :)
3 0
3 years ago
The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?
Serhud [2]

Answer:

b = \sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}

Step-by-step explanation:

Given - The circumference of the ellipse approximated by C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi }  =  \sqrt{\frac{a^{2} + b^{2} }{2} }

Squaring Both sides, we get

[\frac{C}{2\pi }]^{2}   =  [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2}  }   =  {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2}  }   =  {{a^{2} + b^{2} }

\frac{C^{2} }{2(\pi )^{2} }  = a^{2} + b^{2} \\\frac{C^{2} }{2(\pi )^{2} }  -  a^{2} = b^{2} \\\sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}  = b

∴ we get

b = \sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}

8 0
3 years ago
Which statement best describes f(x)= -2 √x-7 +1 –6 is in the domain of f(x) but not in the range of f(x). –6 is not in the domai
Archy [21]

Answer:

B. -6 does not belong to the domain but belongs to the range of f(x).

Step-by-step explanation:

We have the function, f(x)=-2\sqrt{x-7}+1.

So, the domain of the function is obtained when x-7\geq 0 i.e. x\geq 7

That is, the domain is {x | x≥ 7}.

Now as we have,

x\geq 7 → x-7\geq 0 → \sqrt{x-7} \geq 0 → -2\sqrt{x-7} \leq 0 → -2\sqrt{x-7}+1 \leq 1.

That is, f(x)\leq 1

Thus, the range of the function f(x) is {y | y≤ 1}.

Thus, we can see that,

-6 does not belong to the domain but belongs to the range of f(x).

5 0
3 years ago
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