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FromTheMoon [43]
3 years ago
15

Until a train is a safe distance from the station it must travel at 5 m/s. Once the train is on open track it can speed up to 45

m/s. If it takes a train 8 seconds to reach 45 m/s, what is the acceleration of the train? (Round your answer to the nearest whole number.)
A) 4 m/s2
B) 5 m/s2
C) 6 m/s2
D) 7 m/s2
Mathematics
2 answers:
jok3333 [9.3K]3 years ago
6 0
The  answer is 5 because acceleration=change speed/change time
change time=8
change speed=45-5=40
40/8=5

5  m/s^2 is acceleration
Aneli [31]3 years ago
3 0
<span>The correct answer is B) 5 m/s</span>²<span>.

Explanation<span>:
To find acceleration, we find the ratio of the change in velocity to the change in time. The change in velocity is 45-5=40. It takes 8 seconds, so the change in time is 8. 40/8=5.</span></span>
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Which of the following statements describes the process for solving 4x ≥ -24?
arsen [322]

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Step-by-step explanation:

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5 0
3 years ago
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see explanation

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7 0
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Need help ^^^^^^^^^^
NeX [460]
The answer is B. 2y+3
this is proven by multiplying the divisor of the original question and the solution
(y-5)(2y+3)&#10;  2y^{2}+3y-10y-15&#10;  2y^{2}-7y-15
4 0
3 years ago
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