Answer:
1. So, it's basically y=mx + b, you put the b first like y= 2/3x -1, and the b is negative, so you go down on the y-axis one time and the 2/3x is rise over run 2 is the rise and 3 is the run.
for y=-x -4 you put a denominator for -x like -1/1x you keep the denominator positive.
2. If the 2x is in the incorrect spot you put it on the other side and it's a positive, so you put is as a negative on the other side, so you're left with
-y=-2x-1, but you can't have a sign on them, so you divide it with -1 and on the other side as well, so it comes down to y=2x+1 and if the x doesn't have a denominator you add a one to it, like this y=2/1x+1 and you put the 1 on the y-axis and its a positive so you go up one time and the rise or run is 2/1, so you start at 1 on the y-axis and you rise 2 times, so 3-axis and run 1 time and it's 1-axis.
For the last one ill do it on paper.
Answer:
huh try multiplying
Step-by-step explanation:
The given identity tells you ...
.. (sum of numbers) * (sum of squares - product) = (sum of cubes)
Substituting the given information, you have
.. (sum of numbers) * (29 -10) = 133
Then you can divide by (29 -10) to get
.. sum of numbers = 133/19 = 7
The sum of the two numbers is 7.
The answer is D
You just need to subtract term 1 (5) from term 2 (10) to find the answer, and the common difference between each sequential term is 5
The range of the equation is 
Explanation:
The given equation is 
We need to determine the range of the equation.
<u>Range:</u>
The range of the function is the set of all dependent y - values for which the function is well defined.
Let us simplify the equation.
Thus, we have;
This can be written as 
Now, we shall determine the range.
Let us interchange the variables x and y.
Thus, we have;
Solving for y, we get;
Applying the log rule, if f(x) = g(x) then 
, then, we get;
Simplifying, we get;
Dividing both sides by 
, we have;
Subtracting 7 from both sides of the equation, we have;
Dividing both sides by 2, we get;
Let us find the positive values for logs.
Thus, we have,;
The function domain is
By combining the intervals, the range becomes
Hence, the range of the equation is
