10C4 represent the Combinations of 10 objects taken 4 at a time.
The formula for nCr is:
In the given case, n=10 and r=4. Using these values we get:
This means we can make 210 combinations of 10 objects taken 4 at a time.
Answer:
Its 40 for the first and 20for the other one
Step-by-step explanation:
I just took the test.
Answer:
180
Step-by-step explanation:
its 180 cos its the closest number to 193 that 18 can go in, your overall answer to the equation is 310 remainder 13. But I dont know if u need that..
Answer:
I wanna say its D. $259.67
Step-by-step explanation:
Some one should back my answer but I hope this helps you
65 sequences.
Lets solve the problem,
The last term is 0.
To form the first 18 terms, we must combine the following two sequences:
0-1 and 0-1-1
Any combination of these two sequences will yield a valid case in which no two 0's and no three 1's are adjacent
So we will combine identical 2-term sequences with identical 3-term sequences to yield a total of 18 terms, we get:
2x + 3y = 18
Case 1: x=9 and y=0
Number of ways to arrange 9 identical 2-term sequences = 1
Case 2: x=6 and y=2
Number of ways to arrange 6 identical 2-term sequences and 2 identical 3-term sequences =8!6!2!=28=8!6!2!=28
Case 3: x=3 and y=4
Number of ways to arrange 3 identical 2-term sequences and 4 identical 3-term sequences =7!3!4!=35=7!3!4!=35
Case 4: x=0 and y=6
Number of ways to arrange 6 identical 3-term sequences = 1
Total ways = Case 1 + Case 2 + Case 3 + Case 4 = 1 + 28 + 35 + 1 = 65
Hence the number of sequences are 65.
Learn more about Sequences on:
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