I need help please the question is in the picture.

Mathematics

1 answer:

Basile [38]3 years ago

7 0

Answer:

5x+12=42

x=6

Step-by-step explanation:

8+x+x+2+3x+2=42

5x+12=42

5x=42-12

5x=30

x=6

You might be interested in

Write any equation in slope intercept form of the line that passes through the given point and it's parallel to the graph of the

Orlov [11]

Paralalell means that is has the same slope
y=mx+b
m=slope
y=-1x-2
slope=-1

the equation of a line that passes through the point (x1,y1) and has a slope of m is y-y1=m(x-x1)
given
(2,-2) and slope is -1
y-(-2)=-1(x-2)
y+2=-x+2
minus 2
y=-x
answer is y=-x

4 0

2 years ago

Which of the following functions best describes this graph?

Nadusha1986 [10]

Answer:

(A). y = ( x - 3 ) ( x + 4 )

Step-by-step explanation:

5 0

2 years ago

In a function can the y value have more than one x value?

LiRa [457]

Answer:

Yes the y value an have more than one x value BUT the x value can only have one y value.

Step-by-step explanation:

example if we have 1 and it goes to 2 the 1 cant go to another number such as 3.. if we had another number like 4 and it goes to 2 like the 1 it would be acceptable

hope this helped and is not to confusing-

7 0

3 years ago

What is the ratio 75 centimeters to 3 meters

sergey [27]

75:3 is equivalent to 25:1 or just 25

3 0

3 years ago

What is the discontinuity and zero of the function f(x) = 3x^2 + x - 4 / x-1

7nadin3 [17]

Ans: Option (1) <span>Discontinuity at (1, 7), zero at ( negative four thirds , 0)
</span>
Explanation:
Given function:
$f(x) = \frac{3x^2 + x - 4}{x-1}$

Now if we plug in the x = 1, we would have discontinuity as function goes to infinity.

Now for f(1):
$f(x) = \frac{3x^2 + x - 4}{x-1} \\ f(x) = \frac{3x^2 + 4x - 3x - 4}{x-1} \\ f(x) = \frac{x(3x+4)-1(3x+4)}{x-1} \\ f(x) = \frac{(x-1)(3x+4)}{(x-1)} \\ f(x) = 3x+4 \\ now ~ insert ~ x=1: \\ f(1) = 3(1) + 4 = 7 \\ It~means~discontinuity~at~(1,7).\\ Now~let~us~find~zeros.\\ put~ f(x) = 3x+4 ~ equals~ to ~zero. \\ =\ \textgreater \ ~3x+4 = 0 \\ =\ \textgreater \ ~ x = \frac{-4}{3} \\ Hence~zeros=( \frac{-4}{3}, 0)$

5 0

3 years ago